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Step2247 [10]
3 years ago
9

Why will the value of y for the function y equals 5x + 1 always be greater than that of y equals 4x + 1 with X greater than 1?

Mathematics
2 answers:
klemol [59]3 years ago
4 0
You mean
the linear equations, 5x-y+1=0,4x-y+1=0
the slopes are 5 and 4 respectively.
it is clear that slope of first equation is greater that is it has a steeper graph therefore it Will always be greater than the other for x > 1
the same can be done by calculus; differentiation.

note y=5x+1 is always greater than y=4x+1 for all x>1
Yanka [14]3 years ago
4 0

Because 5 times any number > 1 will always be greater then 4 times any number > 1.

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Answer:

AB = 16 Units

Step-by-step explanation:

In the given figure, CD is the diameter and AB is the chord of the circle.

Since, diameter of the circle bisects the chord at right angle.

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Let the center of the circle be given by O. Join OA.

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Triangle OAE is right triangle.

Now, by Pythagoras theorem:

OA^2 = AE^2 + OE^2 \\10^2 = AE^2 + 6^2 \\100=  AE^2 + 36\\100-36 = AE^2 \\64= AE^2 \\AE = \sqrt{64}\\AE = 8 \\\because AB = 2AE..[From \: equation\: (1)] \\\therefore AB = 2\times 8\\\huge \purple {\boxed {AB = 16 \: Units}}

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3 years ago
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Tems11 [23]

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Step-by-step explanation:

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3 years ago
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Answer:

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Lera25 [3.4K]

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