Find a cubic function with the given zeros. -6, 7, -4

Mathematics

1 answer:

Nookie1986 [14]3 years ago

7 0

$f(x)=a(x-x_1)(x-x_2)(x-x_3)\\\\x_1=-6;\ x_2=7;\ x_3=-4\\\\f(x)=(x+6)(x-7)(x+4)=(x^2-x-42)(x+4)\\\\=x^3+3x^2-46x-168$

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