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Olegator [25]
3 years ago
8

20th term of 12, 15, 18, 21

Mathematics
1 answer:
Rainbow [258]3 years ago
7 0

Answer:

69

Step-by-step explanation:

The rule: 3n+9

n=20

3(20)+9

60+9

69

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If A and B are two points having coordinates (- 2, 2) and (2,-4) respectively, find the coordinates of P such that AP= AB.​
Karo-lina-s [1.5K]

Answer:

(0,1)

Step-by-step explanation:

The mid point of A(-2,2) and B(2,-4) is the coordinates of point P, which is (x,y)

Hence, the line AB = AP + PB.

At point AP: x = (-2+2)/2 = 0

also, point PB: y = (2 - 4)/2 = -1

Therefore, coordinates of point P = (0,-1)

7 0
3 years ago
The graph of the function f(x) = x3 – 7x – 6 intersects the x-axis at the points (–2, 0), (–1, 0), and (3, 0) as shown. Which ex
Alisiya [41]
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Answer: (x + 2) (x + 1) (x - 3)
5 0
3 years ago
If AB=9, the diagram blank the case of a degenerate triangle because blank. The case of a degenerate triangle justifies the use
sesenic [268]

Answer:

Step-by-step explanation:

4 0
3 years ago
Which equation can we use to solve the following?<br> 42 · X = 16
Kazeer [188]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The volume of a hemisphere is 144 pi. Find the radius and total surface area.
sineoko [7]
Formula of the Volume of a hemisphere:
V = \frac{2}{3}\pir³
144\pi = \frac{2}{3}\pir³
Multiply by 3 to cancel fraction in the right side
144\pi × 3 = 2\pi r³
432 \pi = 2\pir³
Divide by 2\pi on either sides to isolate r³
\frac{432 \pi }{2 \pi } = \frac{2 \pi }{2 \pi }r³
2\pi and 2 \pi cancel out
216 = r³
Take cube root to find the radius
\sqrt[3]{216} = \sqrt[3]{r^3}
6 = r
Radius is 6 units

The formula of the surface area of a hemisphere is:
S.A = 2\pir² + \pir²
       = 2\pi(6)² + \pi(6)²
       =2\pi × 36 + 36\pi
       = 72\pi + 36\pi
       = 108\pi units²  (in terms of \pi)
       ≈ 339.12 units²

Surface area = 108\pi units
8 0
3 years ago
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