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3 years ago

Solving systems of equations by substitution y= x - 8 y = -4

Mathematics

1 answer:

leva [86]3 years ago

4 0

It should be x=-4 and y= -12

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Varvara68 [4.7K]

10 feet in guessing Bc it’s 9.5 and the nearest tenth is 10

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3 years ago

What is ¼(x - 8) = 1.5

bekas [8.4K]

I think the answer is 14

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3 years ago

Convert the circle to standard form.<br><img src="https://tex.z-dn.net/?f=%20%7B9x%7D%5E%7B2%7D%20%20%2B%20%20%7B9y%7D%5E%7B2%7D

lara31 [8.8K]

Answer:

(x + 1)² + (y + 1)² = (√6)²

Step-by-step explanation:

Group the x- and y- terms together:

9x^2 + 18x + 9y^2 + 9y = 36

Factor out the coefficient 9:

x^2 + 2x + y^2 + y = 4

Complete the square of x^2 + 2x and then do the same for y^2 + 2y:

x^2 + 2x + 1 - 1 + y^2 + 2y + 1 - 1 = 4

Rewrite x^2 + 2x + 1 as the square of the binomial x + 1:

(x + 1)^2 + (y + 1)^2 - 2 = 4

Collect the constant terms on the right side:

(x + 1)^2 + (y + 1)^2 = 6

Rewrite 6 as (√6)^2:

(x + 1)² + (y + 1)² = (√6)² is the equation in standard form (x - h)² + (y - k)² = r²

Completing the square is done as follows: x^2 + 2x

Start with x^2 + 2x

1. Take half of the coefficient of x, which results in 2/2, or 1

2. Square this result and add it to, and subtract it from x^2 + 2x

x^2 + 2x + 1 - 1

3. Rewrite the first three terms as the square of a binomial:

x^2 + 2x + 1 - 1 = (x + 1)² - 1.

Do the same for y² + 2y.

7 0

3 years ago

How do you find the average rate of change of a function over an interval?

Kaylis [27]

Average rate of change over an interval =

(difference in value of the function between the
beginning and end of the interval)
divided by
(length of the interval).

Example:

If the function was 200 pounds at the beginning, and 98 pounds 3 hours later,
then the average rate of change is (98 - 200) / 3 = -34 pounds per hour.

5 0

4 years ago

Given the following data for resting heartrate among college students, what is the IQR? 57, 59, 60, 62, 62, 63, 64, 68, 70, 70,

aev [14]

Answer:

Step-by-step explanation:

The inter-quartile range (IQR) is the difference between the third and first quartile. The data gathered is:

57, 59, 60, 62, 62, 63, 64, 68, 70, 70, 71, 71, 73, 79, 87, 89, 90

The data set has 17 values, the first quartile is the average between the 4th and 5th values, while the third quartile is the average between the 13th and 14th values:

$Q_1 = \frac{62+62}{2}=62\\Q_3 = \frac{73+79}{2}=76$

The IQR is:

$IQR = Q_3 - Q_1 = 76 -62\\IQR = 14$

8 0

3 years ago