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Gnoma [55]
3 years ago
14

How do u write 3:4 and 6:8 as a fraction proportion

Mathematics
2 answers:
S_A_V [24]3 years ago
7 0

you would just change the columns to a dash. The answer is 3/4 and 6/8


I hope this helps. :)

faltersainse [42]3 years ago
3 0

3/4=6/8

hope this helps :)

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The two figures are congruent find the measure of the requested side or angle
antiseptic1488 [7]
You have not provided the figures, therefore, I cannot provide an exact answer.
However, I can helps you with the steps.

One important thing to note is that when writing statements of congruency, the order of writing the letters is very important. This is because each side/angle in the first figure would be congruent to the corresponding side/angle in the second.

Therefore, all you have to do in the above question is write the congruent figures and determine the corresponding congruent sides/angles

Example:
If we are given that triangle ABC is congruent to triangle DEF
This means that:
AB = DE
BC = EF
AC = DF
angle A = angle D
angle B = angle E
angle C = angle F

Hope this helps :)
4 0
3 years ago
Find the partial fraction decomposition of the rational expression with prime quadratic factors in the denominator
SpyIntel [72]
\dfrac{5x^4-7x^3-12x^2+6x+21}{(x-3)(x^2-2)^2}=\dfrac{a_1}{x-3}+\dfrac{a_2x+a_3}{x^2-2}+\dfrac{a_4x+a_5}{(x^2-2)^2}
\implies 5x^4-7x^3-12x^2+6x+21=a_1(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(a_4x+a_5)(x-3)

When x=3, you're left with

147=49a_1\implies a_1=\dfrac{147}{49}=3

When x=\sqrt2 or x=-\sqrt2, you're left with

\begin{cases}17-8\sqrt2=(\sqrt2a_4+a_5)(\sqrt2-3)&\text{for }x=\sqrt2\\17+8\sqrt2=(-\sqrt2a_4+a_5)(-\sqrt2-3)\end{cases}\implies\begin{cases}-5+\sqrt2=\sqrt2a_4+a_5\\-5-\sqrt2=-\sqrt2a_4+a_5\end{cases}

Adding the two equations together gives -10=2a_5, or a_5=-5. Subtracting them gives 2\sqrt2=2\sqrt2a_4, a_4=1.

Now, you have

5x^4-7x^3-12x^2+6x+21=3(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(x-5)(x-3)
5x^4-7x^3-12x^2+6x+21=3x^4-11x^2-8x+27+(a_2x+a_3)(x-3)(x^2-2)
2x^4-7x^3-x^2+14x-6=(a_2x+a_3)(x-3)(x^2-2)

By just examining the leading and lagging (first and last) terms that would be obtained by expanding the right side, and matching these with the terms on the left side, you would see that a_2x^4=2x^4 and a_3(-3)(-2)=6a_3=-6. These alone tell you that you must have a_2=2 and a_3=-1.

So the partial fraction decomposition is

\dfrac3{x-3}+\dfrac{2x-1}{x^2-2}+\dfrac{x-5}{(x^2-2)^2}
7 0
3 years ago
How do you find the square root of a number?
joja [24]
By taking square root of a number using calculator
5 0
3 years ago
George is trying to make sure his garden is in the form of a right triangle. Which of the following side lengths would create a
torisob [31]
Your answer would be 15 m if i’m doing it right
5 0
3 years ago
What is this answer plz help
scZoUnD [109]

Answer:

y=-3/4

i think

6 0
2 years ago
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