If the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
Consider the first odd integer as x
Then the next consecutive odd integer = x+2
The 6 times the second integer= 6(x+2)
= 6x+12
Sum of an integer and 6 times the next consecutive odd integer is 61
Then the equation will be
x + 6x+12 = 61
Add the like terms in the equation
(1+6)x + 12 = 61
7x +12 = 61
Move 12 to the right hand side of the equation
7x = 61-12
7x = 49
x = 49/7
x = 7
The second number is
x+2 = 7+2
= 9
Hence, if the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
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Answer:
Square
Step-by-step explanation:
square - (geometry) a plane rectangle with four equal sides and four right angles
The simplified expression is b+8.9
Add both together by combing like terms to get 8x^2-x-4
Answer:
3/10 + 4/10
1/2 + 1/5
1/10 + 3/5
Step-by-step explanation:
3/10 + 4/10 = 7/10 (add numerator and keep denominator)
1/2 + 1/5 = 5/10 + 2/10 = 7/10 (use equivalent fractions)
1/10 + 3/5 = 1/10 + 6/10 = 7/10
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