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Arte-miy333 [17]
3 years ago
13

What is the factored form of this expression? 4t2 − 27t + 18 A. (4t − 3)(t − 6) B. (2t − 9)(2t − 2) C. (4t − 18)(t − 1) D. (2t −

6)(2t − 3)
Mathematics
1 answer:
coldgirl [10]3 years ago
4 0

Answer:

A

Step-by-step explanation:

You can try it on a calculator

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allochka39001 [22]

Answer:

math a app good luck with the question

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3 years ago
Find the product. <br> 2 x (–8) x (–9)<br><br><br><br> 19<br><br> –19<br><br> –144<br><br> 144
chubhunter [2.5K]
The answer is 144

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4 0
3 years ago
Finding Present Value In Exercise,complete the table to determine the amount of money P that should be invested at rate r to pro
valkas [14]

Answer:

Step-by-step explanation:

The principal was compounded monthly. This means that it was compounded 12 times in a year. So

n = 12

The rate at which the principal was compounded is 4%. So

r = 4/100 = 0.04

The formula for compound interest is

A = P(1+r/n)^nt

A = total amount in the account at the end of t years. The total amount is given as $100000.

1) When t is 1,

100000 = P(1+0.04/12)^12×1

100000 = P(1+0.0033)^12

100000 = P(1.0033)^12

P = 100000/1.04

P = $96154

2) When t is 10

100000 = P(1+0.04/12)^12×10

100000 = P(1+0.0033)^120

100000 = P(1.0033)^120

P = 100000/1.485

P = $67340

3) When t is 20

100000 = P(1+0.04/12)^12×20

100000 = P(1+0.0033)^240

100000 = P(1.0033)^240

P = 100000/2.2

P = $45455

4) When t is 30

100000 = P(1+0.04/12)^12 × 30

100000 = P(1+0.0033)^360

100000 = P(1.0033)^360

P = 100000/3.274

P = $30544

5) When t is 40

100000 = P(1+0.04/12)^12 × 40

100000 = P(1+0.0033)^480

100000 = P(1.0033)^480

P = 100000/4.862

P = $20568

6)When t is 50

100000 = P(1+0.04/12)^12 × 50

100000 = P(1+0.0033)^600

100000 = P(1.0033)^600

P = 100000/7.22

P = $13850

5 0
3 years ago
Help plz asap..... . ​
LenKa [72]

Answer:

Y=1

Step-by-step explanation:

cause 2x0/2 + 4 x 0 + 1 = 1

6 0
3 years ago
Read 2 more answers
If g(x) = -3x+1= 16 what does x equal?
Alex787 [66]
16 = -3x+1
15 = -3x
-5 = x
8 0
3 years ago
Read 2 more answers
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