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Arte-miy333 [17]

3 years ago

13

What is the factored form of this expression? 4t2 − 27t + 18 A. (4t − 3)(t − 6) B. (2t − 9)(2t − 2) C. (4t − 18)(t − 1) D. (2t −

6)(2t − 3)

1 answer:

coldgirl [10]3 years ago

4 0

Answer:

A

Step-by-step explanation:

You can try it on a calculator

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Find the volume of each figure. Round your answers to the nearest tenth, if necessary

olga nikolaevna [1]

Answer:

1.92 m³

hopefully this answer can help you to answer the next question.

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3 years ago

Mandy shaded the fraction strip below to represent a fraction Shade the fraction strip below so that it represents a fraction th

Aleksandr-060686 [28]

Your question is missing the figure, so the figure for your question is attached below:

Answer:

shade 2 strips out of 4 to get fraction strip equivalent to Mandy's fraction strip

Step-by-step explanation:

As Mandy shaded the 3 trips out of the total six strips. It shows the fraction of $\frac{3}{6}$

and $\frac{3}{6}=\frac{1}{2}$

To shade the given fraction strip so that it represents a fraction that is equivalent to Mandy's fraction strip, we should shade 2 stripes out of 4 that is equivalent to $\frac{1}{2}$

i.e. $\frac{2}{4}=\frac{1}{2}$

My Fraction Strip is equivalent to Mandy's Fraction Strip because both are equal to $\frac{1}{2}$

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3 years ago

M^3+9m<br> Factoring. Please help

Verdich [7]

M^3 + 9m =

There is a common factor of m.

= m(m^2 + 9)

That is the complete factorization.
m^2 + 9 is a sum of two squares which is not factorable.

Answer: m(m^2 + 9)

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3 years ago

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If m∠D = 18°, and m∠C = 45°, what is ?

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<span>the question is, If m∠D = 18° and m∠C = 45° what is arc BC? your answer is B. 54 degrees </span>

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A running circuit is in the shape of a triangle with lengths of 6km, 6.5km and 7km. What are the sizes of the angles (in minutes

Rudik [331]

A <u>triangle</u> is an example of a class of <em>figures</em> referred to as <em>plane shapes</em>. It has <u>three</u> straight <u>sides</u> and <u>three</u> internal <u>angles</u> which sum up to $180^{o}$ . The <em>measures</em> of the internal <u>angles</u> of the <u>triangle</u> given in the question are A = $52.6^{o}$ , B = $59.4^{o}$ , and C = $68^{o}$ .

A <u>triangle</u> is an example of a class of <em>figures</em> referred to as <em>plane shapes</em>. It has <u>three</u> straight <u>sides</u> and <u>three</u> internal <u>angles</u> which sum up to $180^{o}$ .

Considering the given question, let the <u>sides</u> of the triangle be: a = 6 km, b = 6.5 km, and c = 7 km.

Apply the <em>Cosine rule</em> to have:

$c^{2}$ = $a^{2}$ + $b^{2}$ - 2ab Cos C

So that;

$7^{2}$ = $6^{2}$ + $(6.5)^{2}$ - 2(6 * 6.5) Cos C

49 = 36 + 42.25 - 78Cos C

78 Cos C = 78.25 - 49

= 29.25

Cos C = $\frac{29.25}{78}$

= 0.375

C = $Cos^{-1}$ 0.375

= 67.9757

C = $68^{o}$

Apply the <em>Sine rule</em> to determine the <u>value</u> of B,

$\frac{b}{Sin B}$ = $\frac{c}{Sin C}$

$\frac{6.5}{Sin B}$ = $\frac{7}{Sin 68}$

SIn B = $\frac{6.5 *Sin 68}{7}$

= 0.861

B = $Sin^{-1}$ 0.861

= 59.43

B = $59.4^{o}$

Thus to determine the value of A, we have;

A + B + C = $180^{o}$

A + $59.4^{o}$ + $68^{o}$ = $180^{o}$

A = $180^{o}$ - 127.4

= 52.6

A = $52.6^{o}$

Therefore the <u>sizes</u> of the <em>internal angles</em> of the triangle are: A = $52.6^{o}$ , B = $59.4^{o}$ , and C = $68^{o}$ .

For more clarifications on applications of the Sine and Cosine rules, visit: brainly.com/question/14660814

#SPJ1

8 0

2 years ago