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blondinia [14]
3 years ago
14

Determine algebraically whether the function is even, odd, or neither even nor odd. f(x)=2/x^2

Mathematics
1 answer:
melomori [17]3 years ago
7 0
An even function can be reflected across the y axis and map onto itself
example: f(x)=x²
an easy test is
if a function is even, then f(-x)=f(x)

an odd function can be reflected about the origin and map onto itself
example: f(x)=x³
a functio is odd if f(-x)=-f(x)


assuming ya meant f(x)=\frac{2}{x^2}

test the f(-x)=f(x) thing

f(x)=\frac{2}{x^2}
f(-x)=\frac{2}{(-x)^2}
f(-x)=\frac{2}{((-1)(x))^2}
f(-x)=\frac{2}{(-1)^2(x)^2}
f(-x)=\frac{2}{1x^2}
f(-x)=\frac{2}{x^2}

yep, same

it is even
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