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insens350 [35]
2 years ago
5

PLEASEE HELL find the solution to the system of equations

Mathematics
2 answers:
seropon [69]2 years ago
7 0

Answer:

(-3, -4)

Step-by-step explanation:

y= -4

so you plus y in for the y=2x+2 equation where you get x=-3

Sergio [31]2 years ago
4 0

\huge\text{Hey there!}

\large\text{If y = -4 then SUBSTITUTE it into the EQUATION}

\large\text{-4 =  2x + 2}

\large\text{TURN  the EQUATION}

\large\text{2x + 2 = -4}

\large\text{SUBTRACT by 2 to BOTH SIDES}

\large\text{2x + 2 - 2 = -4 - 2}

\large\text{CANCEL out: 2 - 2 because that gives you 0}

\large\text{Keep: -4 - 2 because it helps us solve for x}

\large\text{2x = -6}

\large\text{DIVIDE by 2 to BOTH SIDES }

\mathsf{\dfrac{2x}{2}=\dfrac{-6}{2}}

\large\text{CANCEL out: }\mathsf{\dfrac{2}{2}} \large\text{because that gives you 1}

\large\text{KEEP: }\mathsf{\dfrac{-6}{2}}  \large\text{because it gives us the value of x }

\boxed{\boxed{\large\text{Answer: \bf x = -3}}}\huge\checkmark\\\\\boxed{(-3,-4)}

\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

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What is the vertex of f (x) = 5x^2+20x-16
sergeinik [125]

Answer:

vertex = (- 2, - 36)

Step-by-step explanation:

Given a parabola in standard form : y = ax² + bx + c : a ≠ 0

Then the x- coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

f(x) = 5x² + 20x - 16 is in standard form

with a = 5, b = 20 and c = - 16

x_{vertex} = - \frac{20}{10} = - 2

Substitute x = - 2 into f(x) for corresponding y- coordinate

f(- 2) = 5(- 2)² +20(- 2) - 16 = 20 - 40 - 16 = - 36

vertex = (- 2, - 36)



3 0
2 years ago
Read 2 more answers
What are the possible values of x in 8x2 + 4x = -1?
Westkost [7]

Answer:

The possible values of x are:

x= \frac{-1+\sqrt{3}}{4} \,\,or\,\, x= 0.18

and

x= \frac{-1-\sqrt{3}}{4} \,\, or \,\, x= -0.68

Step-by-step explanation:

8x^2+4x+1=0

Using Quadratic formula to solve this equation:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\a = 8 \,\, b = 4\,\, c = -1\\Putting \,\, values \,\, in \,\, the\,\, equation\\x= \frac{-4\pm\sqrt{(4)^2-4(8)(-1)}}{2(8)}\\x= \frac{-4\pm\sqrt{16+32}}{16}\\x= \frac{-4\pm\sqrt{48}}{16}\\x= \frac{-4+ \sqrt{48}}{16} \,\, and \,\, x= \frac{-4- \sqrt{48}}{16}\\x= \frac{-1+ \sqrt{3}}{4} \,\, and \,\, x= \frac{-1- \sqrt{3}}{4}

The possible values of x are:

x= \frac{-1+\sqrt{3}}{4} \,\,or\,\, x= 0.18

and

x= \frac{-1-\sqrt{3}}{4} \,\, or \,\, x= -0.68

4 0
3 years ago
In slope-intercept form what is m=-2, b=8/5
Harman [31]

Answer:

y = -2x + 8/5

Step-by-step explanation:

6 0
3 years ago
A grasshopper jumps straight up from the ground with an initial vertical velocity of 8 feet per second. After how many seconds w
vlabodo [156]

Answer:

Problem 1 : After 0.25 s

Problem 2 : The squirrel doesn't reach the ground before the nut

Step-by-step explanation:

Problem 1

This is a standard physics problem

The equation that defines the movement of the grasshopper given the initial velocity, and the acceleration is the following

Distance =  Do + Vo*t + 0.5*a*t^2

Where

Do is the initial distance.

(Do = 0, because the grasshopper is on the ground and we choose the reference system there)

Vo is the initial velocity = 8 feet/sec

a is the acceleration that is exerted on the body (in this case a = g = -9.8 m/s^2 = - 32.174 feet per second per second.)

t is the time

We substitute in the equation, and solve for t (time)

Distance =  Do + Vo*t + 0.5*a*t^2

(1 foot)=  (0)+ (8 feet/s)*t + 0.5*(-32.174 feet/s^2)*t^2

Solving this equation, we get that

t = 0.25 s

Problem 2

This problem is similar to the previous one

We apply the same formula

D =  Do + Vo*t + 0.5*a*t^2

But in this case, we are going in the opposite direction, and we have an initial distance.

Do = 27 feet

Vo is the initial velocity of the nut = -6 feet/s

D = 0  (Ground)

We substitute in the equation, and solve for t (time)

(0) =  (27) + (-6 feet/s)*t + 0.5*(-32 feet/s^2)*t^2

t = 1.125 s  <  2s

The nut reaches ground in 1.125 s, so the squirrel doesn't reach the ground before the nut

4 0
3 years ago
How do you do these geometry?
siniylev [52]

Answer:

The angles are 45°, 60° , 75°

Step-by-step explanation:

<h3>Angle sum property:</h3>

Sum of all the angles of a triangle is 180°.

Equation:  

     3x + 5x + 4x = 180

Combine like terms,

                   12x = 180

                      x = 180/12

                      \sf \boxed{x = 15}

3x = 3 *15 = 45°

5x = 5* 15 = 75°

4x = 4 *15 = 60°

4 0
1 year ago
Read 2 more answers
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