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What is the area of the following circle?
1 answer:
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Looking at the problem, you can come up with an equation for the consecutive numbers.
If we expand the second term:
Combine like terms:
You can reduce this by dividing both sides of the equation by two:
And we transpose 170 to get a standard quadratic form that the right side will be zero:
Then factor the left side:
Find out the values of x that makes each factor = 0
x + 14 = 0
x = -14
We can eliminate the negative symbol because the problem is asking for positive even integers.
and;
x - 12 = 0
x = 12
Now we can say that the first positive integer is 12 and the second one is 14
If we expand the second term:
Combine like terms:
You can reduce this by dividing both sides of the equation by two:
And we transpose 170 to get a standard quadratic form that the right side will be zero:
Then factor the left side:
Find out the values of x that makes each factor = 0
x + 14 = 0
x = -14
We can eliminate the negative symbol because the problem is asking for positive even integers.
and;
x - 12 = 0
x = 12
Now we can say that the first positive integer is 12 and the second one is 14
Area of an equilateral triangle is 
, where s is length of a side; we have s = 2 + 4 + 2 = 8 mm; then area is 
;
Area of a semi-circle = (1/2)π
, where r is the radius of circle; r = 4/2 = 2 mm; then area is 2π;
The shaded area is![16 \sqrt{3} - 2π = 2( [tex]8 \sqrt{3}](https://tex.z-dn.net/?f=16%20%5Csqrt%7B3%7D%20-%202%CF%80%20%3D%202%28%20%5Btex%5D8%20%5Csqrt%7B3%7D%20)
- π );
Area of a semi-circle = (1/2)π
The shaded area is