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3 years ago

[Annie: 4 (x+y+z) Bradley: 4x+yz Carlos: 4xyz Zuri: 4x+4z+4y]

2 answers:

8 0

4x+4y+4z. I was taught to take out what was in each term, in this problem that would be 4: 4(X+y+z). Meaning A) Annie did the problem right :) I hope this helps!

garri49 [273]3 years ago

7 0

Answer:

Annie

Step-by-step explanation:

In the expression

$4x+4y+4z$

All terms have in common the coefficient of 4, so we can take it out (or factor it) from the expression as follows:

$4(x+y+z)$

and due to the distributive property, in which the 4 must be multiplied by each of the terms within the parenthesis, this is equivalent to the original expression.

Thus, the student who has the right answer is: Annie.

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Find the average value of the function on the given interval.<br> f(x)=2 ln x; [1,e]

JulijaS [17]

Answer:

$f_{avg}=\frac{1}{e-1}$

Step-by-step explanation:

We are given that a function

$f(x)=2lnx$

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Average value of function on interval [a,b] is given by

$\frac{1}{b-a}\int_{a}^{b}f(x)dx$

Using the formula

$f_{avg}=\frac{1}{e-1}\int_{1}^{e}lnx dx$

By Parts integration formula

$\int(uv)dx=u\int vdx-\int(\frac{du}{dx}\int vdx)dx$

u=ln x and v=dx

Apply by parts integration

$f_{avg}=\frac{1}{e-1}([xlnx]^{e}_{1}-\int_{1}^{e}(\frac{1}{x}\times xdx))$

$f_{avg}=\frac{1}{e-1}(elne-ln1-[x]^{e}_{1})$

$f_{avg}=\frac{1}{e-1}(e-0-e+1)=\frac{1}{e-1}$

By using property lne=1,ln 1=0

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3 years ago

X-7=13answer and how to solve?

Ahat [919]

X-7=13
move -7 to the right side of the equation, change the sign from negative to positive when you move it
x-7+7=13+7
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3 years ago

Emily's account balance this Monday is -$8.35 . Her account balance last Monday was $15.75. Which statement explains how to find

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The correct answer to determine the change in he account is by:

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Hope This helped :)

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3 years ago

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Step-by-step explanation:

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Andre45 [30]

Answer:

Step-by-step explanation:

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3 years ago

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