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Mama L [17]
3 years ago
13

I don’t know the unit rate to this problem

Mathematics
1 answer:
Ierofanga [76]3 years ago
8 0

Answer:

Since its counting by 2 go between 0 and 2 which is one and go up the blue line so the answer is 10

Step-by-step explanation:

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PLEASE HELP!!!!! Factor completely 16x8 − 1
Delvig [45]

Answer:

see explanation

Step-by-step explanation:

This is a difference of squares and factors in general as

a² - b² = (a - b)(a + b)

16x^{8} = ( 4x^{4} )² ⇒ a = 4x^{4}

1 = 1² ⇒ b = 1

Hence

16x^{8} - 1

= (4x^{4} )² - 1²

= (4x^{4} - 1)(4x^{4} + 1)

4x^{4} - 1 ← is also a difference of squares and factors as

(2x² - 1)(2x² + 1)

Thus

16x^{8} - 1

= (2x² - 1)(2x² + 1)(4x^{4} + 1 )

6 0
3 years ago
Read 2 more answers
Which expression is not equivalent to
zheka24 [161]

Answer:

B i think I'm kinda sure tho

b

7 0
2 years ago
Geometry help. Inscribing circle help and constructing lines.
prohojiy [21]
<h3>1. Inscribe a circle ΔJKL. Identify the point of concurrency that is the center of the circle you drew. </h3>

To inscribe a circle in the attached triangle, we must follow the following steps. The resultant figure is the first one below.

1. Draw the angle bisector of angle JKL. The straight line in the green one.

2. Draw the angle bisector of angle KLJ. The straight line in the blue one.

3. Draw point D at these two lines.

4. Draw a line through point D perpendicular to side JK. The straight line in the red one.

5. Mark point G at the red line and side JK.

6. Draw a circle with center at D (point of concurrency) and a radius of DG.


<h3>2. Circumscribe a circle ΔFGH. Identify the point of concurrency that is the center of the circle you drew. </h3>

To circumscribe a circle in the attached triangle, we must follow the following steps:

1. Draw the perpendicular bisector of the side FG. The straight line in the red one. The resultant figure is the second one below.

2. Draw the perpendicular bisector of the side GH. The straight line in the blue one.

3. The center of the circle is the intersection of these two lines

4. Draw a circle with center at D (point of concurrency).

<h3>3. Construct the two lines tangents to circle</h3>

A tangent to a circle is a straight line that touches the circle at an only point. If a point A is outside a circle, we can draw two lines that pass through this point and are tangent to the circle at two different points each. So this is shown in the third figure. Lines red and blue are tangent to the circle at two different points.

3 0
3 years ago
Help me again pls :D sorry for the bother
matrenka [14]

Answer:

A

Step-by-step explanation:

2x2.5x3= 15

2x2.5x4.5=22.5

2.5x3x4=30

2.5x2x4=20

6 0
2 years ago
Read 2 more answers
How to graph 9x+5y=-45
lilavasa [31]
9x +5y= -45 put in standard form y= mx+b coefficient of x is the slope, b is the y intercpept 5y= -9x -45 y= -9/5 x -45 graphing will start at -45 on the y axis from that point go down 9 to the right 5 for the slope continue and graph minimum 2 points to draw the line hope this helps
8 0
3 years ago
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