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3 years ago

Given v^2 = u^2 − 2as. Solve for u, when v = 10, a = 5 and s = 2.

Mathematics

1 answer:

iogann1982 [59]3 years ago

3 0

Answer:

u ≈ 11

Step-by-step explanation:

10² = u² - 2(5)(2)

100 = u² - 20

120 = u²

u = $\sqrt{120}$

u = $\sqrt{4}$ $\sqrt{30}$ = 2 $\sqrt{30}$ which is 10.95

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Eleni bought 3 packs of crayons. She then found 3 crayons in her desk Eleni now has 24 crayons. How many crayons were in each pa

Mama L [17]

Answer:

7 crayons in each pack

Step-by-step explanation:

1. subtract the 3 found crayons from the total (24)

24-3 = 21

2. divide 21 by 3 packs

21/3 = 7

5 0

3 years ago

A = {a, b, c, d}

Helen [10]

Answer:

Johnny is wrong.

$A \cup B = \left\{a,b,c,d,e,f,g,h\right\}$

Step-by-step explanation:

Johnny is wrong.

A better definition would be: $A \cup B$ is the set of all elements that belong to at least one A or B.

So, the elements that belong to both A and B, like c and d in this exercise, also belong to $A \cup B$ .

So:

$A \cup B=\left\{a,b,c,d,e,f,g,h\right\}$

4 0

3 years ago

The total monthly profit for a firm is P(x)=6400x−18x^2− (1/3)x^3−40000 dollars, where x is the number of units sold. A maximum

wlad13 [49]

Answer:

Maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

Step-by-step explanation:

We are given the following information: $P(x) = 6400x - 18x^2 - \frac{x^3}{3} - 40000$ , where P(x) is the profit function.

We will use double derivative test to find maximum profit.

Differentiating P(x) with respect to x and equating to zero, we get,

$\displaystyle\frac{d(P(x))}{dx} = 6400 - 36x - x^2$

Equating it to zero we get,

$x^2 + 36x - 6400 = 0$

We use the quadratic formula to find the values of x:

$x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}$ , where a, b and c are coefficients of $x^2, x^1 , x^0$ respectively.

Putting these value we get x = -100, 64

Now, again differentiating

$\displaystyle\frac{d^2(P(x))}{dx^2} = -36 - 2x$

At x = 64, $\displaystyle\frac{d^2(P(x))}{dx^2} < 0$

Hence, maxima occurs at x = 64.

Therefore, maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

6 0

3 years ago

Why does -2(x + 3y) = 18 equal y=-3-x/3? Please helppp

Citrus2011 [14]

Step-by-step explanation:

You're asking why

${- 2(x + 3y) = 18} = y = - 3 - \frac{x}{3}$

let's transpose the first equation for y

-2x-6y=18

-6y=18+2x

6y=-18-2x

y=-18/6-2x/6

y=-3-⅓x as required

8 0

3 years ago

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What is the Identity Property of Multiplication?

Scilla [17]

Answer:

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3 years ago

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