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Sergio039 [100]
3 years ago
15

In the figure below, if sin x=5/13, what are cos x and tan x

Mathematics
1 answer:
Afina-wow [57]3 years ago
4 0
Please show the figure
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He counted 206 wheels and 170 pedals. How many bicycles and tricycles does he have.
noname [10]
Bicycle has 2 wheels and 2 pedals
 tricycle has 3 wheels and 2 pedals

EQ 1 : 2b + 2t = 170 pedals

 EQ 2: 2b +3t = 206 wheels

subtract  EQ 1 from EQ 2

2b +3t = 206 - 2b + 2t = 170 = t=36

 there were 36 tricycles

36 x 2 = 72 pedals

170 pedals - 72 = 98 pedals left
98/2 = 49 bicycles

36 Tricycles and 49 bicycles




8 0
3 years ago
When a set of coordinates on a preimage is multiplied by -n instead of n, the coordinates of the image rotate about the center o
dem82 [27]

Tumhen yah Kahan Se Mila

4 0
3 years ago
Read 2 more answers
An artist is designing a kite like the one show below. Calculate the area to determine how much material she will need to create
neonofarm [45]

Answer:

The answer is 161.5

Step-by-step explanation:

Step-by-step explanation: The top half of the kite is 6 in times 17 in because 8.5 + 8.5 = 17 so its 102. Half of 102 is 51 so 51 is the area of the top half. The bottom half is 13 in times 17 in which equals 221. Half of 221 is  110.5. Then 110.5 + 51 = 161.5... So your answer is 161.5 square inches.

7 0
2 years ago
How do i solve this problem
Vladimir79 [104]
Solve the following system:
{6 t - 5 s = -4 | (equation 1)
{-r - 4 s + 3 t = -4 | (equation 2)
{-2 r - 4 s - 4 t = -9 | (equation 3)

Swap equation 1 with equation 3:
{-(2 r) - 4 s - 4 t = -9 | (equation 1)
{-r - 4 s + 3 t = -4 | (equation 2)
{0 r - 5 s + 6 t = -4 | (equation 3)
Subtract 1/2 × (equation 1) from equation 2:
{-(2 r) - 4 s - 4 t = -9 | (equation 1)
{0 r - 2 s + 5 t = 1/2 | (equation 2)
{0 r - 5 s + 6 t = -4 | (equation 3)
Multiply equation 1 by -1:
{2 r + 4 s + 4 t = 9 | (equation 1)
{0 r - 2 s + 5 t = 1/2 | (equation 2)
{0 r - 5 s + 6 t = -4 | (equation 3)
Multiply equation 2 by 2:
{2 r + 4 s + 4 t = 9 | (equation 1)
{0 r - 4 s + 10 t = 1 | (equation 2)
{0 r - 5 s + 6 t = -4 | (equation 3)
Swap equation 2 with equation 3:
{2 r + 4 s + 4 t = 9 | (equation 1)
{0 r - 5 s + 6 t = -4 | (equation 2)
{0 r - 4 s + 10 t = 1 | (equation 3)
Subtract 4/5 × (equation 2) from equation 3:
{2 r + 4 s + 4 t = 9 | (equation 1)
{0 r - 5 s + 6 t = -4 | (equation 2)
{0 r+0 s+(26 t)/5 = 21/5 | (equation 3)

Multiply equation 3 by 5:
{2 r + 4 s + 4 t = 9 | (equation 1)
{0 r - 5 s + 6 t = -4 | (equation 2)
{0 r+0 s+26 t = 21 | (equation 3)
Divide equation 3 by 26:
{2 r + 4 s + 4 t = 9 | (equation 1)
{0 r - 5 s + 6 t = -4 | (equation 2)
{0 r+0 s+t = 21/26 | (equation 3)
Subtract 6 × (equation 3) from equation 2:
{2 r + 4 s + 4 t = 9 | (equation 1)
{0 r - 5 s+0 t = (-115)/13 | (equation 2)
{0 r+0 s+t = 21/26 | (equation 3)
Divide equation 2 by -5:
{2 r + 4 s + 4 t = 9 | (equation 1)
{0 r+s+0 t = 23/13 | (equation 2)
{0 r+0 s+t = 21/26 | (equation 3)
Subtract 4 × (equation 2) from equation 1:
{2 r + 0 s+4 t = 25/13 | (equation 1)
{0 r+s+0 t = 23/13 | (equation 2)
{0 r+0 s+t = 21/26 | (equation 3)
Subtract 4 × (equation 3) from equation 1:
{2 r+0 s+0 t = (-17)/13 | (equation 1)
{0 r+s+0 t = 23/13 | (equation 2)
{0 r+0 s+t = 21/26 | (equation 3)
Divide equation 1 by 2:
{r+0 s+0 t = (-17)/26 | (equation 1)
{0 r+s+0 t = 23/13 | (equation 2)
v0 r+0 s+t = 21/26 | (equation 3)
Collect results:Answer:  {r = -17/26
               {s = 23/13                        {t = 21/26
7 0
3 years ago
PLEASE HELP-
salantis [7]

Answer:

1 3/4 simplified or 1 12/16 not simplified

5 0
3 years ago
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