Solve each system of equations by graphing 4x-y=5 and. 2x+y=7

Mathematics

1 answer:

vivado [14]3 years ago

4 0

4x-y=5 Would be the y-intercept (0,7) 2x+y=7 Would be the x-intercept (3.5,0)
Sorry if wrong

You might be interested in

Triangle ABC is the image of triangle ABC after a translation of 2 units to the night and 3 units

Mariulka [41]

Answer:

yes the triangle is congruent, because you did not use any transformations you on used translations.

but if you used transformations it would be similar not congruent

4 0

3 years ago

Read 2 more answers

2x+2y = 5<br> 3x + 3y = 7<br> How many solutions does the system of equations above have?

Anastaziya [24]

Answer:

No solutions

Step-by-step explanation:

5 0

2 years ago

Can someone help me in this plssss I really need it

kompoz [17]

Answer:

$\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}$

Step-by-step explanation:

Your expression is

$\sqrt [3] {-54x^{5}y^{6}}$

Here's how I would simplify it.

$\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}$

$\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}$