The trick with this problem is that there is no trick - there's no math involved at all, just wordplay. The key is in one-time deposit; what you're looking for isn't a recurring fee, but rather a constant. Now, an equation is made up of three things:
- a variable
- a relational statement in the form of =
- a constant, even if it isn't really there, it's zero
In this case, what you're looking for is the constant in the equation; a value that doesn't change when any variable changes.
The only number in your question that fits the bill is 1200$, since it's a <em>one-time, unchanging value.</em> <em>y </em>is the total amount paid and x represents the months, which are both variables; 400 is tied to x, so it also changes based on months.
Answer:
Step-by-step explanation:
,21
You would take 175 and multiply it by 0.20 which is 35. The you would subtract 35 from 175 because it is marked down so you would get 140. Next, you would take 140 and multiply it by 0.10 and get 14. Finally subtract 14 from 140 to get your answer which would be $126.
Answer:
1) Distance=Speed*time
90=(x+1)*(x)+(2x+5)(x-1)
90=x^2+x+2x^2-2x+5x-5
3x^2+4x-95=0
2) 3x^2+4x-95=0. Using quadratic formula, we get
x=(-4±sqrt(16-4*3*(-95)<u>)</u>)/6, x=5 or - 19/5 but since x also represents time, it can't be negative.
3) Total time take she took for the journey is x+x-1=2x-1=2*5-1=9 hours
