Answer: Reject the eight- ounces claim.
Step-by-step explanation:
For left tailed test , On a normal curve the rejection area lies on the left side of the critical value.
It means that if the observed z-value is less than the critical value then it will fall into the rejection region other wise not.
As per given ,
Objective : A coffee-dispensing machine is supposed to deliver eight ounces of liquid or less.
Then ,
, since alternative hypothesis is left-tailed thus the test is an left-tailed test.
the critical value for z for a one-tailed test with the tail in the left end is -1.645 and the obtained value is -1.87.
Clearly , -1.87 < -1.645
⇒ -1.87 falls under rejection region.
⇒ Decision : Reject null hypothesis.
i.e. we reject the eight- ounces claim.
Answer:
Option 2) Null hypothesis: p = 0.078
, Alternate hypothesis: p > 0.078
Step-by-step explanation:
We are given the following in the question:
According to the National Center of Health Statistics, about 7.8% of all babies born in the U.S. are categorized as low birth weight.
Sample size, n = 1200
p = 7.8% = 0.078
We have to carry a hypothesis test whether national percentage is higher than 7.8% or not.
Thus, we can design the null and the alternate hypothesis
Thus, the correct answer is:
Option 2) Null hypothesis: p = 0.078
, Alternate hypothesis: p > 0.078
Just for you beautiful!
Use distance formula: d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
(11,-4) is (x1,y1) and (-12,-4) is (x2,y2)
Plug in and simplify
d = sqrt((-12 - 11)^2 + (-4 - -4)^2)
d = sqrt((-23)^2 + (0)^2)
d = sqrt(529 + 0)
d = sqrt(529)
d = 23 (positive because length cannot be negative) ;)
