Answer: m(x)=2fhx
I hope this helps
Answer:
1 3/12
Step-by-step explanation:
Oh wait i could read #5 so you make them all have 12 as the denominator then do 78 4/12 - 77 1/12 and you get 1 1/4 or 1 3/12 so then you do 1 3/12 MINUS 77 1/12 and you should get 75 10/12 which is CORRECCTTTTT
THESE ARE THE THREE IN THE TEXT ORDER IN CASE U NEED TO SEE
78 4/12
77 1/12
75 10/12
EVERYTHING IS CORRECTTTTTTTTTTTTTTTTTTTTTT
I really, really don't like this question. People have preferences in solving quadratics. I would personally use, and would encourage anyone to use the quadratic equation. That's because completing the square would get excessively fractional, graphically doesn't even work because the solutions are imaginary, and differentiating it wouldn't be necessary, as there are no irrational numbers (except i, which is just imaginary). So, in short, quadratic equation because you can't get anything graphically, the answers are ugly fractions, and you can actually use that method.
Since it's so nicely grouped, we can work with it! For the equation to equal 0, x=0, 3, or -1 (since x-3 and x+1 equal 0 when plugged in with 3 and -1 respectively). All we have to do is plug in numbers before, between, and after these numbers and apply it to the rest of them. Since -1 is the smallest number of the group, we can plug in a number below that (for this example, -5) and plug it in to get -8*-5*-4= something negative since it contains an odd number of negative numbers. Therefore, anything less than 1 is negative. For between -1 and 0, we get x=-0.5 equals -0.5*-3.5*0.5=something positive (since it has an even amount of negative numbers), proving that everything between -1 and 0 here is positive. For something between 0 and 3, we can plug 1 in to get 1*-2*2= something negative. Do you see a pattern here? It's negative, then positive, etc.. Therefore, if the number is greater than 3 it is positive. Reviewing a bit, we can see that (-inf, -1) is negative as well as (0,3), making the interval notation (-inf, -1) U (0, 3) since when you plug -1, 0, and 3 in it is 0, not less than 0!
Answer:
x^2 - 64
Step-by-step explanation:
A difference of squares is a special product in the form (a^2 - b^2)..their factored form is (a - b)(a + b)..
Thus here a = x and b = 8, thus if x + 8 is a factor, then x - 8 is also a factor..
(x + 8)(x - 8) <-- expand this out using difference of squares rules..
= (x)^2 - (8)^2
= x^2 - 64 <-- answer...
You could also expand that using FOIL (FOIL - first, outer, inner, last)..
(x + 8)(x - 8)
= (x)(x) + (x)(-8) + (8)(x) + (8)(-8)
= x^2 - 8x + 8x - 64 <-- the -8x and 8x cancels out..leaving you with..
= x^2 - 64
