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Rufina [12.5K]
3 years ago
8

Triangle SQT is isosceles. The measure of angle STQ is 48°. Triangle S Q T is cut by perpendicular bisector T R. The lengths of

line segments S R and R Q are congruent. Side lengths S T and T Q are congruent. Angles S T R and R T Q are congruent. What is the measure of Angle S T R? 24° 38° 48° 76°
Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
7 0

Answer:

A.24

Step-by-step explanation:

igomit [66]3 years ago
3 0

Answer:

m\angle STR=24^o

Step-by-step explanation:

we know that

m\angle STQ=m\angle STR+m\angle RTQ ---> by addition angle postulate

we have

m\angle STQ=48^o ----> given problem

m\angle STR=m\angle RTQ ----> given problem

substitute in the expression above

48^o=2m\angle STR

Divide by 2 both sides

m\angle STR=24^o

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What is the lateral area of the pyramid
Mkey [24]

Answer:

43.75 ft²

Step-by-step explanation:

s_l = (l√(w/2)² + h²) + (w√(l/2)² + h²)

l & w become 3.5, and h becomes 6.

<em />s_l<em> </em>= (3.5√(3.5/2)² + 6²) + (3.5√(3.5/2)² + 6²)

<em>Step 1:Because this is a square pyramid, what you see above essentially becomes what you see below.</em>

<em />s_l = 2(3.5√(3.5/2)² + 6²)

<em>Step 2: Divide 3.5 by 2 to get 1.75.</em>

<em />s_l<em> </em>= 2(3.5√1.75² + 6²)

<em>Step 3: Square both 1.75 and 6 to get 3.0625 and 36 respectively.</em>

s_l = 2(3.5√3.0625 + 36)

<em>Step 4: Add 3.0625 and 36 to get 39.0625.</em>

<em />s_l = 2(3.5√39.0625)

<em>Step 5: The square root of 39.0625 is 6.25.</em>

<em />s_l<em> </em>= 2(3.5 * 6.25)

<em>Step 6: Multiply 3.5 by 6.25 to get 21.875.</em>

<em />s_l = 2(21.875)

<em>Step 7: Multiply 2 by 21.875 to get 43.75.</em>

<em />s_l = 43.75 ft²

The lateral area of this pyramid is 43.75 ft².

<em />

<em />

3 0
2 years ago
A hovercraft takes off from a platform. Its height (in meters), xxx seconds after takeoff, is modeled by: h(x)=-2x^2+20x+48h(x)=
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the maximum height is the y-value of the vertex.

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Answer:

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Step-by-step explanation:

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