Answer:
Marco will need 
of material to make the kite
Step-by-step explanation:
we know that
To know how much material Marco will need to make the kite, the area must be calculated.
Remember that the area of the kite is equal to
![A=\frac{1}{2}[d1*d2]](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%5Bd1%2Ad2%5D)
where
d1 and d2 are the diagonals of the kite
we have
substitute
![A=\frac{1}{2}[2*3]=3\ ft^{2}](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%5B2%2A3%5D%3D3%5C%20ft%5E%7B2%7D)
Answer:
sinH ≈ 0.47
Step-by-step explanation:
sinH = 
= 
= 
≈ 0.47 ( to the nearest hundredth )
Answer:
the equation should be corrected to fit the data of the problem. With the corrected equation a mass of 0.5 grams remains after 150 years
Step-by-step explanation:
for the mass y( in grams)
y=23* (1/2)^(t/45), t ≥ 0.
the initial mass is at t=0 , then
y= 23 grams → should be 16 grams
half-life from the equation = 45 years → should be 30 years
the correct equation should be
y=16*(1/2)^(t/30), t ≥ 0
then after 150 years → t= 150
y=16*(1/2)^(150/30)= 16*(1/2)^5 = 16/32 = 0.5 grams
then a mass of 0.5 grams remains after 150 years
