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tia_tia [17]
4 years ago
4

Which of the variable expressions below is a trinomial with a constant term? A. 3x5 – 2x3 B. x5 – 3x2 + 5x C. 7x6 + 2x4 – x3 + 7

D. 4x2 – 3 + x3
Mathematics
1 answer:
lesya [120]4 years ago
4 0

Answer:

Option (D)

Step-by-step explanation:

Option (A).

3x⁵ - 2x³

There are two terms with the variable 'x' in the given expression. therefore, it's a binomial with no constant term.

Option (B).

x⁵ - 3x² + 5x

This expression has three terms with variable 'x'.

Therefore, it's a trinomial without no constant term.

Option (C).

7x⁶ + 2x⁴ - x³ + 7

It's a quadrinomial having 4 terms. '7' is the constant term in the given expression.

Option (D).

4x² + x³ - 3 ≈ x³ + 4x² - 3

It's a trinomial with a constant term 3.

Therefore, Option (D) is the answer.

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Use the graph of △ABC with midsegments DE, EF and DF. Show that EF is parallel to AC and that EF=1/2 AC
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According to the midsegment theorem, the midsegments are parallel to

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The completed statement are as follows;

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From the given graph of ΔABC, we have;

Coordinates of the points <em>A</em>, <em>B</em>, and <em>C </em>are; A(-5, 2), B(1, -2), and C(-3, -6)

The coordinates of the point D and E on \mathbf{\overline{DE}} are; D(-4, -2), and E(-2, 0)

The coordinates of the point F is; F(-1, -4)

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\displaystyle Slope \ of \ line \ \overline{AC} = \mathbf{\frac{(-6) - 2}{-3 - (-5)}  = \frac{-8}{2}} = -4

\displaystyle Slope \ of \ line \ \overline{EF} = \frac{0 - (-4)}{-2 - (-1)}  = \frac{4}{-1} = -4

  • Length \ of \ segment,\ l = \sqrt{\left (x_{2}-x_{1}  \right )^{2}+\left (y_{2}-y_{1}  \right )^{2}}

Length of EF  = √((-1 - (-2))² + (-4 - 0)²) = √(17)

Length of AC = √((-3 - (-5))² + (-6 - 2)²) = √(4 × 17) = 2·√(17)

Therefore, we have;

Because the slope of \mathbf{\overline {EF}} and \mathbf{\overline {AC}} are both , <u>-4</u>, \overline {EF} ║ \overline {AC}. EF = \underline{\sqrt{17}}, and AC

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