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AURORKA [14]
3 years ago
14

In a parallelogram if AB = 3x + 2y and AB = 30 what is the value of x and y

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
5 0
We can put the two equations together with substitution, and we get

3x + 2y = 30

Now we have a single equation in two variables, so we don't have enough information to solve for both x and y.
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HELP ME QUICK PLEASEEEE solve for x: 2/x-2+7/x^2-4=5/x
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\displaystyle\\3x^2-11x-20=0\\\\x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{11\pm\sqrt{121+4\cdot3\cdot20}}{2\cdot3}=\\\\=\frac{11\pm\sqrt{121+240}}{6}=\frac{11\pm\sqrt{361 }}{6}=\frac{11\pm19}{6}\\\\x_1=\frac{11-19}{6}=\frac{-8}{6}\\\\\boxed{\bf x_1=-\frac{4}{3}}\\\\x_2=\frac{11+19}{6}=\frac{30}{6}\\\\\boxed{\bf x_2=5}




3 0
3 years ago
PLEASEEE EXPLAIN AND HELP
Firdavs [7]

The length of the unknown sides of the triangles are as follows:

CD = 10√2

AC = 10√2

BC =  10

AB = 10

<h3>Triangle ACD</h3>

ΔACD is a right angle triangle. Therefore, Pythagoras theorem can be used to find the sides of the triangle.

  • c² = a² + b²

where

c = hypotenuse side = AD = 20

a and b are the other 2 legs

lets use trigonometric ratio to find CD,

cos 45 = adjacent / hypotenuse

cos 45 = CD / 20

CD = 1 / √2 × 20

CD = 20 / √2 = 20√2 / 2 = 10√2

20² - (10√2)² = AC²

400 - 100(2)  = AC²

AC² = 200

AC = √200 = 10√2

<h3>Triangle ABC</h3>

ΔABC is a right angle triangle too. Therefore,

  • AB² + BC² = AC²

Using trigonometric ratio,

cos 45 = BC / 10√2

BC = 10√2 × cos 45

BC = 10√2 × 1 / √2

BC = 10√2 / √2 =  10

(10√2)² - 10² = AB²

200 - 100 = AB²

AB² = 100

AB = 10

learn more on triangles here: brainly.com/question/24304623?referrer=searchResults

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Answer:

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20<em>A</em><em>n</em><em>s</em>

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Select the correct answer. Simplify. Reset Submit
DaniilM [7]
I think it is submit
Hope this helps
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