It is a positive-slope parabola with vertex of (0,16) "concave up"
To prove <QPR = <QRP we have to prove ΔPTR ≅ ΔRSP
Let T be the mid point of PQ and S be the mid point of QR
line joining T and S is TS parallel to PR
Triangle PTR and triangle RSP have same base, one side equal and between same parallel are congruent.
Therefore ΔPTR ≅ ΔRSP by CPCTC <QPR = <QRP
So we can cnclude that PQR is an isosceles triangle.
Answer:
a b c d e f
Step-by-step explanation:
all good
Answer:
a=88
b=82
Step-by-step explanation:
perimeter=2(l+w)
302=2(l+63)
302=2l+126
2l=176
l=88
A=l×w
8118=99×82
w=82
Answer:
A) x²/25 + y²/9 = 1
Step-by-step explanation:
The major axis length is the sum of distances to the foci from the ellipse, 10. So the semi-major axis has length 10/2 = 5. The foci are on the x-axis, so the ellipse is oriented horizontally.
The semi-minor axis is the other leg of the right triangle having the focus and center as one leg, and the semi-major axis as the hypotenuse. This is obviously a 3-4-5 triangle, so the semi-minor axis length is 3.
When the ellipse is horizontal, the formula for it is ...
... (x/(semi-major axis))² + (y/(semi-minor axis))² = 1
... (x/5)² + (y/3)² = 1
... x²/25 + y²/9 = 1