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2 years ago

What is the common ratio for this geometric sequence 3,12,48,192,... A 16 B. 3 C. 4 D. 9

Mathematics

1 answer:

hram777 [196]2 years ago

3 0

Answer:

Step-by-step explanation:

The common ratio is found by taking the second term and dividing by the first term

12/3 = 4

We can check by taking the third term and dividing by the second

48/12 = 4

The common ratio is 4

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Given <br><img src="https://tex.z-dn.net/?f=%20log_%7B2%7D%28x%29%20%20%3D%20%20%5Cfrac%7B3%7D%7B%20log_%7Bxy%7D%282%29%20%7D%20

Naily [24]

Answer:

$\displaystyle y = x^{-\frac{2}{3}}$

Step-by-step explanation:

<u>Logarithms</u>

Some properties of logarithms will be useful to solve this problem:

1. $\log(pq)=\log p+\log q$

2. $\displaystyle \log_pq=\frac{1}{\log_qp}$

3. $\displaystyle \log p^q=q\log p$

We are given the equation:

$\displaystyle \log_{2}(x) = \frac{3}{ \log_{xy}(2) }$

Applying the second property:

$\displaystyle \log_{xy}(2)=\frac{1}{ \log_{2}(xy)}$

Substituting:

$\displaystyle \log_{2}(x) = 3\log_{2}(xy)$

Applying the first property:

$\displaystyle \log_{2}(x) = 3(\log_{2}(x)+\log_{2}(y))$

Operating:

$\displaystyle \log_{2}(x) = 3\log_{2}(x)+3\log_{2}(y)$

Rearranging:

$\displaystyle \log_{2}(x) - 3\log_{2}(x)=3\log_{2}(y)$

Simplifying:

$\displaystyle -2\log_{2}(x) =3\log_{2}(y)$

Dividing by 3:

$\displaystyle \log_{2}(y)=\frac{-2\log_{2}(x)}{3}$

Applying the third property:

$\displaystyle \log_{2}(y)=\log_{2}\left(x^{-\frac{2}{3}}\right)$

Applying inverse logs:

$\boxed{y = x^{-\frac{2}{3}}}$

7 0

3 years ago

A is 5 years older than T. In 3 years, T will be 2/3 A age. How old is A?

Ivanshal [37]

Answer:

12 years

Step-by-step explanation:

T + 5 = A

Therefore T =A - 5

In three years T = 3+ (A-5)

thus T = A - 2

Also in three years T = 2/3 (A+3)

Equating the two

A -2 = 2/3 (A+3)

3A - 6 = 2A + 6

3A - 2A = 6 + 6

Therefore A = 12

6 0

3 years ago