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3 years ago

What type of number can be written as a fraction, where p and q are

Mathematics

1 answer:

Alex17521 [72]3 years ago

3 0

Answer:

A. rational number can be written p/q form, where q not equal to zero.

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Can someone please help?

maria [59]

x = 3x - 70 as corresponding angles

2x = 70

x = 35

∠LMN = 3x - 70 = 3*35 - 70 =35⁰

∠LMN = 35⁰

3 0

3 years ago

Half of the sum of 32 and 2

dimaraw [331]

Answer:

Step-by-step explanation:

32+2=34

34/2= 17

7 0

3 years ago

6c+31=4c+13 this question is equation formulae and inequalities

Sergio039 [100]

Answer:

Step-by-step explanation:

6c+31=4c+13

6c - 4c = 13 - 31

2c = -18

c = -9.

6 0

2 years ago

BC is tangent to circle A at B and to circle D at C. AB=9, BC=26, and DC=8. Find AD to the nearest tenth.

Ksju [112]

There are two circles with center A and D. The tangent line touches both point B and C. The given measurements are enough to solve for the missing value and the solution is shown below:
AB=9
BC=26
DC=8
Solve for the measurement of AC which the hypotenuse of legs AB and BC by Pythagorean theorem:
c²=a²+b²
c²=9²+26²
c=AC=27.51
Solve for angle of A
sin A=26/27.51
A=70.93°
Finally, we solve for the length of AD using SOH
sin 70.93°=AD/27.51
AD=26
The answer is 26.

3 0

3 years ago

Using the Rational Root Theorem, what are all the rational roots of the polynomial f(x) = 20x4 + x3 + 8x2 + x – 12?

igomit [66]

Answer:

Option 1 is correct.

Step-by-step explanation:

The given polynomial is

$f(x)=20x^4+x^3+8x^2+x-12$

we have to find all the rational roots of the polynomial f(x)

The Rational Root Theorem states that the all possible roots of a polynomial are in the form of a rational number i.e in the form of $\frac{p}{q}$

where p is a factor of constant term and q is the factor of coefficient of leading term.

In the given polynomial the constant is -12 and the leading coefficient is 20.

$\text{All possible factor of -12 are }\pm1,\pm2, \pm3, \pm4,\pm6,\pm12$

$\text{All possible factor of 20 are }\pm1,\pm2,\pm4,\pm5,\pm10,\pm20$

So, the all possible rational roots of the given polynomial are,

$\pm1,\pm2, \pm3, \pm4,\pm6,\pm12,\pm\frac{1}{2},\pm\frac{3}{2},\pm\frac{1}{4},\pm\frac{3}{4},\pm\frac{1}{10},\pm\frac{1}{5},\pm\frac{3}{5},\pm\frac{3}{10},\pm\frac{2}{5},\pm\frac{6}{5},\pm\frac{1}{20},\pm\frac{3}{20},\pm\frac{4}{5},\pm\frac{12}{5}$

Now, the rational roots of polynomial satisfy the given polynomial

$f(-\frac{4}{5})=20(-\frac{4}{5})^4+(-\frac{4}{5})^3+8(-\frac{4}{5})^2-\frac{4}{5}-12=\frac{256}{625}\times 20-\frac{64}{125}+\frac{128}{125}-\frac{4}{5}-12$