Answer:
The vector joining the ship to the rock is t= 7 i + 5 j
The direction is 0.9505 radians east of north.
Step-by-step explanation:
The position vector of the ship:
r= 1 i + 0 j
The position vector of the ship:
s= 6 i + 5 j
The vector joining the ship to the rock is:
t = r + s
t = (1 i + 0 j) + (6 i + 5 j)
t = 7 i + 5 j
The bearing of the rock to the ship is:
Θ= 
= 0.9505 radians
Answer a = 5 and b = 2.
Procedure
Initially means x = 0, then
5 = a*b^0 = a*1 = a, then a = 5
When x = 1, the height is the double of 5, i.e 10 and
10 = a.b^1 = a.b ⇒ b = 10/a = 10/5 = 2
The a = 5 and b = 2, so the equation is y =5(2)^x
The distance from a to c is ten units
Answer:
False
Step-by-step explanation:
Counterexample:
If i = 2, then the answer will be 16 and not 1.
