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Scilla [17]
3 years ago
8

Write 23/9 as a decimal. If necessary, use a bar to indicate which digit or group of digits repeats.

Mathematics
1 answer:
seropon [69]3 years ago
5 0

Answer:

2.55555556

Step-by-step explanation:

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The first term of a geometric sequence is 3 and the multiplier, or ratio, is 2. what is the sum of the first 6 terms of the sequ
storchak [24]
Answer:

288

Explanation:

As first term in sequence is 3 so multiplying it by common ratio 5 we get 15, then multiplying 15 by 5 we get 45 and so on the sequence is
<span>3,15,45,225</span>
whose sum is 288

5 0
3 years ago
V^2=12^2+2(-6)(9) answer please i am waitind
il63 [147K]

Answer:

V = 6 or V = -6

Step-by-step explanation:

Solve for V over the real numbers:

V^2 = 12^2 - 6 2 9

12^2 + 2 (-6) 9 = 36:

V^2 = 36

Take the square root of both sides:

Answer: V = 6 or V = -6

3 0
3 years ago
Read 2 more answers
A watercolor painting is 24 inches long by 11 inches wide. Ramon makes a border around the watercolor painting by making a mat t
sergeinik [125]

Given: It is given that the length of the painting is 24 inches and the width is  11 inches.

To find: Area of the mat

Solution:

The watercolor painting is 24 inches long by 11 inches wide.

So, the area of the painting is:

\text{Area of painting}=l\times b

\text{Area of painting}=24\times 11

\text{Area of painting}=264 \text{ in}^2

The length of painting with mat is = 24 in + 3 in + 3 in = 30 in

The width of painting with mat = 11 in + 3 in + 3 in = 17 in

\text{Area of painting with mat}=30\times 17

\text{Area of painting with mat}=510 \text{ in}^2

Now to calculate the area of mat subtracts the area of painting from the area of the mat.

\text{Area of mat}=\text{Area of painting with mat}-\text{Area of painting}\\

\text{Area of mat}=510-264

\text{Area of mat}=246 \text{ in}^2

Hence, the area of the mat is 246 in².

6 0
2 years ago
Find the slope of each line
dimaraw [331]

Answer:

The slope of the blue line is undefined

Step-by-step explanation:

This is because a vertical line cannot have a numerical value for it's slope. Also, there is no y-intercept

4 0
3 years ago
Whats the area of a quarter-circle with diameter of 4 meters
kkurt [141]
The answer is 3.14 m

The area (A) of the circle with radius r is: A = π · r²
The area of the quarter of the circle is: A1 = 1/4A = 1/4 · π · r²

We have:
A1 = ?
r = ?
π = 3.14
d = 4 m

A diameter d is the twice of the radius r: d = 2r.
Therefore, the radius is the half of the diameter: r = d/2
So, the area of the quarter circle would be:
A1 = 1/4 · π · r² = 1/4 · π · (d/2)² =1/4 · π · d²/2² = 1/4 · π · d²/4 = 1/16 · π · d²

A1 = 1/16 · π · d² = 1/16 · 3.14 · 4² = 1/16 · 3.14 · 16 = 3.14 m
5 0
3 years ago
Read 2 more answers
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