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Troyanec [42]
3 years ago
11

The cost of membership at local country club is $125 per family member per month. Each family also has to pay $75 in service fee

s. Model the cost, C, for a membership for a family with x members.
a. C(x) = 75x
b. C(x) = 125x
c. C(x) = 125x 75
d. C(x) = 125 75x
Mathematics
2 answers:
gogolik [260]3 years ago
7 0

Answer:

bbc

Step-by-step explanation:

ihave a bbc

katen-ka-za [31]3 years ago
6 0
To write the equation you start with the 125 because it is monthly and it doesn't say how often you pay the 75 dollars so the equation would be c(f)=125x+75
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Given:

\sigma_A=3

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\sigma_B=5

n_B=4

\overline{x}_A=\overline{x}_B

To find:

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Solution:

Formula for variance is

\sigma^2=\dfrac{\sum (x_i-\overline{x})^2}{n}      ...(i)

Using (i), we get

\sigma_A^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{n_A}

(3)^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}

9=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}

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Similarly,

\sigma_B^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{n_B}

(5)^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}

25=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}

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Now, after combining both sets, we get

\sigma^2=\dfrac{\sum (x_i-\overline{x}_A)^2+\sum (x_i-\overline{x}_B)^2}{n_A+n_B}

\sigma^2=\dfrac{54+100}{6+4}

\sigma^2=\dfrac{154}{10}

\sigma^2=15.4

Therefore, the variance of combined set is 15.4.

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wel
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SOVA2 [1]

Answer:

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Step-by-step explanation:

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Hey there!

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Hope this helps
Have a great day (:
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Step-by-step explanation: That's the best I got.

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