Answer:
So we have a triangle and a semicircle.
If the triangle is equilateral, this is:
AB = BC = 6cm
Then the area of the triangle is equal to (base*height)/2
in this case:
A = (6*6)/2 = 36/2 = 18cm^2.
And the diameter of the semicircle is equal to 6cm, then the diameter is 3cm
And if the area of a circle is A = pi*r^2
then the area of half a circle is:
A = (pi/2*)3^2 = pi*4.5cm^2
Then, the area of the triangle plus the area of the semicircle is:
Total area = 18cm^2 + pi*4.5^2
In Jaden's yard, there I smiled. ...?
Here's the link to the answer:
https://riverside.rocks/index.php
<h2>
Answer:</h2>
The raduis of the circle is given to Id.p. The raduis is 8.5 m. Calculate the lower bonds and the upper bonds:
Answer:
plus or minus square root 50
Step-by-step explanation:
x^2 = 50
Take square root of both sides
x = +/ - √50
Answer:
plus or minus square root 50
