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slava [35]
2 years ago
12

Find the area and the perimeter of the shaded regions below. Give your answer as a completely simplified exact value in terms of

π (no approximations). The figures below are based on semicircles or quarter circles and problem b), and are involving portions of a square.

Mathematics
1 answer:
____ [38]2 years ago
3 0

Answer:

So we have a triangle and a semicircle.

If the triangle is equilateral, this is:

AB = BC = 6cm

Then the area of the triangle is equal to (base*height)/2

in this case:

A = (6*6)/2 = 36/2 = 18cm^2.

And the diameter of the semicircle is equal to 6cm, then the diameter is 3cm

And if the area of a circle is A = pi*r^2

then the area of half a circle is:

A = (pi/2*)3^2 = pi*4.5cm^2

Then, the area of the triangle plus the area of the semicircle is:

Total area = 18cm^2 +  pi*4.5^2

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The lateral edge PA of a triangular pyramid ABCP is perpendicular to the base and PA = 2sqrt5 in. The base edges AB = 10 in, AC
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Answer:

PQ = √84 = 2√21 in ≈ 9.165 in

Step-by-step explanation:

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ΔAQC a right triangle at Q

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Equating (1) and (2)

∴  10² - x² = 17² - (21-x)²

∴ 10² - x² = 17² - (21² - 42x + x²)

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∵ The lateral edge PA of a triangular pyramid ABCP is perpendicular to the base

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PA = 2sqrt5 in  and AQ = 8 in

∴ PQ (hypotenuse) = √(PA² + AQ²)

∴ PQ = √[(2√5)² + 8²] = √(20+64) = √84 = 2√21 in ≈ 9.165 in

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