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IgorC [24]
3 years ago
6

4^2 times 4^8 ?????????

Mathematics
1 answer:
Talja [164]3 years ago
8 0
The answer is 4^10

How to do it:
4^2•4^8 goes into
4^2+8 which 2+8=10
So,
The answer: 4^10
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If a: b = 2:3, b: c = 4:3, and c: d = 7: 8, find a: d.
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Answer:

a:d=7:9

Step-by-step explanation:

We have a system with 3 equation:

\frac{a}{b}=\frac{2}{3}\\\frac{b}{c}=\frac{4}{3}\\\frac{c}{d}=\frac{7}{8}

If we multiply all of these equations, then we have:

\frac{a}{b}*\frac{b}{c}*\frac{c}{d}=\frac{2}{3}*\frac{4}{3}*\frac{7}{8}\\\frac{a*b*c}{b*c*d}=\frac{2*4*7}{3*3*8}\\\frac{a}{d}=\frac{56}{72}

If we simplify this fraction dividing by 9, then:

\frac{a}{d}=\frac{56:9}{72:9}=\frac{7}{9}

Therefore, a:d=7:9

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2 years ago
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E=VIT how would I isolate the “V” variable
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Answer:

V =\frac{E}{IT}

Step-by-step explanation:

You can isolate the "V" variable by dividing by IT on both sides:

\frac{E}{IT} =\frac{VIT}{IT}

On the left, the IT from the top and bottom cancel, leaving you with just V:

V =\frac{E}{IT}

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Answer:

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Step-by-step explanation:

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