Your answer is T=36. Hope it helps you!
Given:
and
, AE = BF, and ED = FC.
We prove that AD = BC as follows:
Statement Reason
1.
and
Given
2. AE + ED = AD Segment Addition Postulate
BF + FC = BC
3. AE = BF and ED = FC Given
4. BF + FC = AD Substitution
5. AD = BC Transitivity property
The answer is 750, as you move the decimal over to the right 2 places.
Answer:
a) 2.9%
b) Option B is correct.
The prisoners must be independent with regard to recidivism.
Step-by-step explanation:
Probability that one prisoner goes back to prison = 17% = 0.17
a) The probability that two prisoners released both go back to prison = 0.17 × 0.17 = 0.0289 = 2.89% = 2.9% to 1 d.p
b) The only assumption taken during the calculation is that probability of one of the prisoners going back to prison has no effect whatsoever in the probability that another prisoner goes back to prison. That is the probability that theses two events occur are totally independent of each other.
If they weren't, we wouldn't be able to use 0.17 as the probability that the other prisoner goes back to prison too.