Its is two since you take out the decimals then divide regularly
Answer:
Confidence Interval for the mean
Step-by-step explanation:
Confidence interval is made using the observations of a <em>sample</em> of data obtained from a population, so it is constructed in such a way, that, with a certain <em>level of confidence </em>(this is the statement mentioned in the question), that is, one could have a percentage of probability that the interval, or range around the value obtained, frequently 95%, contains the true value of a population parameter (in this case, the population mean).
It is one way to extract information from a population using a sample of it. This kind of information is what inference statistic is always looking for.
An <u>approximation</u> about how to construct this interval or range:
- Select a random sample.
- For the specific case of a <em>mean</em>, you need to calculate the mean of the <em>sample </em>(sample mean), and, if standard deviation is unknown or not mentioned, also calculate the sample standard deviation.
- With this information, and acknowledged that these values follows a standard normal distribution (a normal distribution with mean 0 and a standard deviation of 1), represented by random variable Z, one can use all this information to calculate a <em>confidence interval for the mean</em>, with a certain confidence previously choosen (for example, 95%), that the population mean must be in this interval or <em>range around this sample mean.</em>
Answer with explanation:
After dilation about the origin(0,0) with the scale factor of 'k" , the image of the original point (x,y) becomes (kx,ky)
From the given graph, the coordinates of point C = (0,6) [Since it lies on y-axis , the x-coordinate is zero]
After a dilation about the origin(0,0) with the scale factor of 
, the new point will be 
Now plot this point on y-axis at y=3 as given in the attachment.
Answer:
5.83 a week
Step-by-step explanation:
do 17.50/3 weeks
Answer:
x = 3 + sqrt(5) or x = 3 - sqrt(5)
Step-by-step explanation:
Solve for x over the real numbers:
2 x^2 - 12 x + 8 = 0
Divide both sides by 2:
x^2 - 6 x + 4 = 0
Subtract 4 from both sides:
x^2 - 6 x = -4
Add 9 to both sides:
x^2 - 6 x + 9 = 5
Write the left hand side as a square:
(x - 3)^2 = 5
Take the square root of both sides:
x - 3 = sqrt(5) or x - 3 = -sqrt(5)
Add 3 to both sides:
x = 3 + sqrt(5) or x - 3 = -sqrt(5)
Add 3 to both sides:
Answer: x = 3 + sqrt(5) or x = 3 - sqrt(5)
