Question

Please solve and explain how. Photo attached

Answer 1

The solution is $x=14$

Explanation:

The given expression is $\frac{6}{x^{2} -3x}=\frac{1}{x}- \frac{5}{x^{2} -3x}$

We need to determine the solution of the expression.

Let us simplify the equation by taking LCM on both sides.

The LCM of $x^{2} -3x$ is $x(x-3)$

Thus, we have,

$\frac{6}{x^{2} -3x}x(x-3)=\frac{1}{x}x(x-3)- \frac{5}{x^{2} -3x}x(x-3)$

Simplifying the terms, we get,

$6=x-3-5$

Subtracting the terms, we have,

$6=x-8$

Subtracting both sides of the expression by 6, we get,

$0=x-14$

Adding both sides of the expression by 14, we have,

$14=x$

Thus, the solution of the equation is $x=14$