1) The inequality that describes the scenario iS:
35 + 12C ≥ 100
2) The minimum number of classes a customer can take for Rebekah to meet her
goal = 6
One-time initial fee = $35
Additional fee per class = $12
Minimum target = $100
Number of classes = C
One-time initial fee + (Additional fee per class) x (Number of classes) ≥ Minimum target
The inequality that describes the scenario is: 35 + 12C ≥ 100
Solve for C to know the minimum number of classes a customer can take for Rebekah to meet her goal
12C > 100 - 35
12C > 65
С ≥ 65/12
C ≥ 5.42
The minimum number of classes a customer can take for Rebekah to meet her goal = 6
Answer:
c
Step-by-step explanation:
Answer:
There was increase in scheduled passenger flights in a certain a country in Last September than in September 1995
Step-by-step explanation:
Given:
No of Flights in Last September = 753,328
No flights in September 1995 = 734,260
Total Number of Flights increased = No of Flights in Last September - No flights in September 1995 =
Total Number of Flights increased in =
The answer is B; x=18 and y = -20
Proof:
Solve the following system:
{4 x + 3 y = 12 | (equation 1)
{7 x + 5 y = 26 | (equation 2)
Swap equation 1 with equation 2:
{7 x + 5 y = 26 | (equation 1)
{4 x + 3 y = 12 | (equation 2)
Subtract 4/7 × (equation 1) from equation 2:
{7 x + 5 y = 26 | (equation 1)
{0 x+y/7 = (-20)/7 | (equation 2)
Multiply equation 2 by 7:
{7 x + 5 y = 26 | (equation 1)
{0 x+y = -20 | (equation 2)
Subtract 5 × (equation 2) from equation 1:
{7 x+0 y = 126 | (equation 1)
{0 x+y = -20 | (equation 2)
Divide equation 1 by 7:
{x+0 y = 18 | (equation 1)
{0 x+y = -20 | (equation 2)
Collect results:
Answer: {x = 18, y = -20