(b-2)(b-2)(b^2+4)
= (b^2-4b+4)(b^2+4)
= b^4-4b^3+8b^2-16b+16
Answer:
There are 16 integers between -3.92 and 12.4
Step-by-step explanation:
If we want to find the integers between two numbers we just need to subtract the integer numbers of the interval.
The integer interval will be:
![[-3,12]](https://tex.z-dn.net/?f=%5B-3%2C12%5D)
Now, we subtract them:

Let's recall that 0 is an integer
Therefore, the answer will be 16.
I hope it helps you!
Answer:
divide
Step-by-step explanation:
divide 26.216 and 128 to get ur anser
%75 I guess unless this is like highschool math