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BartSMP [9]
3 years ago
10

Please help me, I really would appreciate it. I am struggling with this.

Mathematics
1 answer:
AnnZ [28]3 years ago
3 0
2)

let's say the number is "a".

"two more than the number"  ----> a + 2

"five times more than that"  -----> 5 * (a + 2) ---> 5(a + 2)

"the sum of that number and 5 times the number more than 2"

a + 5(a + 2)

"is 26 more than four times the number" ----> = 4*a + 26 ---> = 4a + 26

a + 5(a + 2) = 4a + 26

\bf a+5(a+2)=4a+26\implies a+5a+10=4a+26
\\\\\\
6a-4a=26-10\implies 2a=16\implies a=\cfrac{16}{2}\implies \boxed{a=8}

3)

"eight times the number" ---> 8 * a, or 8a

"3 less than that" ----> 8a - 3

"the number increased by 1" ---> a + 1

"16 times that"  ---> 16(a + 1)

"half that" ----> [ 16(a + 1) ] / 2

\bf 8a-3=\cfrac{16(a+1)}{2}\implies 2(8a-3)=16(a+1)
\\\\\\
16a-6=16a+16\implies \underline{16a-16a}-6=16\implies \stackrel{\textit{inconsistent system}}{-6\ne 16}

4)

\bf \begin{cases}
y=5x+1\\
y-2x-1
\end{cases}\qquad 5x+1=2x-1\implies 5x-2x=-1-1
\\\\\\
3x=-2\implies x=-\cfrac{2}{3}

5)

notice each equation, they're both in slope-intercept form, y = mx + b.

now, notice their slope, is the same for both, notice their y-intercept, it varies.

same slope, different y-intercept simply means, the lines are parallel.
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storchak [24]
 5+2=7 which means there will  be 7 zeros  so it is 10000000 times greater than
7 0
3 years ago
Read 2 more answers
Nalia worked 3.5 hours more than lisa together they worked a total of 18 hours lisa worked h hours
andre [41]

Answer:

7.25 and 10.75 Hours

Step-by-step explanation:

Total hours Nalia and Lisa worked = 18 Hours

Nalia worked 3.5 hours then Lisa which is h hours

⇒h + (h + 3.5) = 18

2h + 3.5 = 18\\2h = 18 - 3.5\\2h = 14.5\\h = \frac{14.5}{2} \\h = 7.25

Lisa has worked for 7.25 hours

Nalia has worked for = 7.25 + 3.5 = 10.75 hours

3 0
3 years ago
How many different​ three-digit numbers can be formed using the digits 1 comma 2 comma 9 comma 6 comma 4 comma 3 comma and 8 wit
lozanna [386]

Answer:

129 468  

Step-by-step explanation:

I'm not sure if you're supposed to reuse the same numbers just in a different Three digit number. Or if you're supposed to use the number one time and one time only. But if not here's there's some numbers that you could use

He basically all You have to do Is take the numbers and turning them into three digit numbers Without repetition.

Hope this helps you!

Also it's saying that 664 is not allowed Because it they are reusing the six When there's no Extra six to use. So remind you not to use the same number twice!

3 0
3 years ago
Finding an irrational number between which given pair of numbers supports the idea that irrational numbers are dense
Fittoniya [83]

Answer:

3.33 and 1/3

Step-by-step explanation:

"Dense" here means that there are infinite irrational numbers between two rational numbers. Also, there are infinite rational numbers between two rational numbers. That's the meaning of dense. Actually, that can be apply to all real numbers, there always is gonna be a number between other two.

But, to demonstrate that irrationals are dense, we have to based on an interval with rational limits, because the theorem about dense sets is about rationals, and the dense irrational set is a deduction from it. That's why the best option is 2, because that's an interval with rational limits.

8 0
3 years ago
Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be
Oksana_A [137]
<h2>Hello!</h2>

The answers are:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

<h2>Why?</h2>

To calculate the speed of the cars, we need to write two equations, one for each car, in order to create a relation between the two speeds and be able to calculate one in function of the other.

So,

Tet be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

x_{FirstCar}=x_o+v*t

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

x_{SecondCar}=x_o+(v+14mph)*t

Now, from the statement that both cars met after 2 hours and 45 minutes, and the distance between to cover (between A and B) is 264 miles,  so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph

Then, since we know that they covered a combined distance equal to 264 miles in 2 hours + 45 minutes, we have:

2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours

Writing the equation:

264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph

So, the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph

We have that the speed of the second car is equal to 55 mph.

Hence, the answers are:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

Have a nice day!

7 0
3 years ago
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