<h3>
Answer:</h3>
90°
<h3>
Step-by-step explanation:</h3>
The polygon has 7 sides, so the total of internal angles will be ...
... 180°×(7 -2) = 900°
The sum is then ...
... x + 146° +122° +142° +140° +110° +142° = 900°
... x + 802° = 900° . . . . . simplify
... x = 98° . . . . . . . . . . . . .subtract 802°
_____
<em>Comment on angle measure formula</em>
The usual formula for computing the total of internal angles of a convex polygon with n sides is ...
... total angle measure = (n -2)×180°
This can be simplified from the fact that the sum of external angles is always 360°. That is, for internal angles a1, a2, ..., an, the sum of external angles is ...
... (180° -a1) +(180° -a2) +... +(180° -an) = 360°
... n×180° -(a1 +a2 +... +an) = 360° . . . . . . collect terms
... n×180° -360° = (a1 +a2 +... +an) . . . . . . add ∑ak -360°
... 180°×(n -2) = a1 +a2 +... +an . . . . . . . . . factor out 180°
Answer:
15/104
Step-by-step explanation:
To divide fractions take the reciprocal (invert the fraction) of the divisor and multiply the dividend. This is the quickest technique for dividing fractions. The top and bottom are being multiplied by the same number and, since that number is the reciprocal of the bottom part, the bottom becomes one.
A standard number cube has 6 sides....
probability of rolling a 5 is 1/6......probability of not rolling a 5 is 5/6
Answer:
15.87% probability that a randomly selected individual will be between 185 and 190 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 180, \sigma = 8](https://tex.z-dn.net/?f=%5Cmu%20%3D%20180%2C%20%5Csigma%20%3D%208)
What is the probability that a randomly selected individual will be between 185 and 190 pounds?
This probability is the pvalue of Z when X = 190 subtracted by the pvalue of Z when X = 185. So
X = 190
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{190 - 180}{8}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B190%20-%20180%7D%7B8%7D)
![Z = 1.25](https://tex.z-dn.net/?f=Z%20%3D%201.25)
has a pvalue of 0.8944
X = 185
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{185 - 180}{8}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B185%20-%20180%7D%7B8%7D)
![Z = 0.63](https://tex.z-dn.net/?f=Z%20%3D%200.63)
has a pvalue of 0.7357
0.8944 - 0.7357 = 0.1587
15.87% probability that a randomly selected individual will be between 185 and 190 pounds