An airliner carries 50 passengers and has doors with a height of 70 in. Heights of men are normally distributed with a mean of 6
9.0 in and a standard deviation of 2.8 in. Complete parts (a) through (d). a. If a male passenger is randomly selected, find the probability that he can fit through the doorway without bending. The probability is 0.6406. (Round to four decimal places as needed.) b. If half of the 50 passengers are men, find the probability that the mean height of the 25 men is less than 70 in. The probability is 0.9633. (Round to four decimal places as needed.)
Let the both the parts be 'x' and 'y' x>y We know that 4x = 5y so x = 5y/4 x + y = 54 Replacing x we get (5y/4) + y = 54 (5y +4y)/4 = 54 9y = 216 y = 24 Replacing y in ' x+y = 54' we get x = 30
Hence the larger part is 30 whereas the smaller part is 24
