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3 years ago

X+4(2+3) < 5x is there a solution??

Mathematics

1 answer:

zavuch27 [327]3 years ago

5 0

Answer:

$\Huge\boxed{\mathsf{\longrightarrow X>5}}$

Step-by-step explanation:

Isolate x on one side of the equation.

First, do parenthesis.

4(2+3)

Add.

3+2=5

Multiply.

4*5=20

Rewrite the equation problem.

x+20<5x

Secondly, subtract 20 from both sides.

x+20-20<5x-20

Solve.

x<5x-20

Thirdly, subtract 5x from both sides.

x-5x<5x-20-5x

Solve.

5-1=4

-4x<-20

Then, multiply -1 from both sides.

(-4x)(-1)>(-20)(-1)

Solve.

(-4x)(-1)=4x

(-20)(-1)=20

4x>20

Divide by 4 from both sides.

4x/4>20/4

Solve.

20/4=5

x>5

$\Large\boxed{\mathsf{\Rightarrow X>5}}}$

The solutions is 5, therefore, the correct answer is x>5.

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$\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{7} \times \:210 \times 210 \: {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{ \cancel{7}} \times \cancel{210} \times 210 \: {m}^{2}}}$

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