Please hurry I have no clue what it is

There are a couple ways to do this, but basically you need to convert the units.

7 yards x 3 ft/yard = 21 feet 
4 yards x 3 ft/yard = 12 feet 
So the area (in sq. ft) will be: 
21 x 12 
= 252 sq. ft. 

Alternatively, you can figure the area in square *yards* and then multiply by 9 sq. ft per sq. yard. 
7 yards x 4 yards x 9 sq. ft/sq. yard 
= 252 sq. ft.

hope this helps :)

4 0

3 years ago

An object is launched from a launching pad 208 ft. above the ground at a velocity of 192ft/sec. what is the maximum height reach

Alexeev081 [22]

Answer:

h(x) = -16x² + 192x + 208

784ft

6 sec

13 sec

Step-by-step explanation:

a)

h(x) = -16x² +vx + h $_{o}$

here v represent velocity

$h_{o}$ represent initial height of launch

h(x) = -16x² + 192x + 208

b)

h(x) = -16x² + 192x + 208

here a = -16

b = 192

c = 208

x = -b/2a

= -192/2(-16)

= 6

plug this value in the equation

h(x) = -16(6)² + 192(6) + 208

= 784ft

e)

Plug h(x)=0 in the equation

0 = -16x² + 192x + 208

divide equation by -16

x² - 12x - 13 = 0

Factors

1x * -13x = -13

1x - 13x = -12

Factorised form

x² - 12x - 13 = 0

x² + x - 13x - 13 = 0

x(x+1) -13(x+1) = 0

(x+1)(x-13) = 0

x = -1

x = 13

Since time can not be negative so we will reject x = -1

3 0

4 years ago