Please hurry I have no clue what it is

cricket20 [7]

F(x) = 2(x + 3), now if we distribute the 2, we get 2x + 6.

we know the lbs of apple is "x", and therefore, the lbs of orange will be the constant 3.

2x will then stand for the price for "x" lbs of apples.

and 2*3 will stand for the price of "3" lbs of oranges, which is 6 bucks.

since the 2 is multiplying the lbs quantity, it must then be the price, so both cost 2 bucks each per pound.

4 0

3 years ago

A national grocery store chain wants to test the difference in the average weight of turkeys sold in Detroit and the average wei

Arte-miy333 [17]

Answer:

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

The null hypothesis is accepted .

Assume the population variances are approximately the same

Step-by-step explanation:

Explanation:-

Given data a random sample of 20 turkeys sold at the chain's stores in Detroit yielded a sample mean of 17.53 pounds, with a sample standard deviation of 3.2 pounds

The first sample size 'n₁'= 20

mean of the first sample 'x₁⁻'= 17.53 pounds

standard deviation of first sample S₁ = 3.2 pounds

Given data a random sample of 24 turkeys sold at the chain's stores in Charlotte yielded a sample mean of 14.89 pounds, with a sample standard deviation of 2.7 pounds

The second sample size n₂ = 24

mean of the second sample "x₂⁻"= 14.89 pounds

standard deviation of second sample S₂ = 2.7 pounds

Null hypothesis:-H₀: The Population Variance are approximately same

Alternatively hypothesis: H₁:The Population Variance are approximately same

Level of significance ∝ =0.05

Degrees of freedom ν = n₁ +n₂ -2 =20+24-2 = 42

Test statistic :-

$t = \frac{x^{-} _{1} - x_{2} }{\sqrt{S^2(\frac{1}{n_{1} } }+\frac{1}{n_{2} } }$

where $S^{2} = \frac{n_{1} S_{1} ^{2}+n_{2}S_{2} ^{2} }{n_{1} +n_{2} -2}$

$S^{2} = \frac{20X(3.2)^2+24X(2.7)^2}{20+24-2}$

substitute values and we get S² = 40.988

$t= \frac{17.53-14.89 }{\sqrt{40.988(\frac{1}{20} }+\frac{1}{24} )}$

t = 1.3622

Calculated value t = 1.3622

Tabulated value 't' = 2.081

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

Conclusion:-

The null hypothesis is accepted

Assume the population variances are approximately the same.

6 0

3 years ago

Find the equations of the line u that cuts the x-axis at x=-6 and the y-axis at y=-4

never [62]

The equation of the line is y = -2/3(x) - 4

5 0

3 years ago

Suppose you roll a six sided number cube one time. What is the probability of rolling a 3 or an even number

Vikki [24]

There are 3 even numbers: 2,4,6. If you add 3 there is 4. There is 6 possible outcomes 1,2,3,4,5,6. So the probability is 4/6, 2/3, 66.666....% or 0.6666666....

8 0

3 years ago

Write an equation of the line below in the picture?

ad-work [718]

I hope my explanation helps

6 0

3 years ago

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