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bixtya [17]
3 years ago
7

ASAP please help me

Mathematics
2 answers:
lesya692 [45]3 years ago
7 0
So his lawn can be divided into 4 shapes: 1 rectangle, 2 triangles, and an irregular shape. So you get the area of the rectangle which is 48*120=5,760.

For the part above the rectangle, you can see that the 2 triangles and the irregular shape make one large triangle so take the area of that. (I’m going to refer to this as the BIG triangle).
.5*40*120=2,400
The base of the triangle is equal to the base of the rectangle. The height of the triangle you get by subtracting the height of the WHOLE lawn by the height of the rectangle. (88-48=40).

Inside that large triangle made up of three shapes, you can see another triangle that’s made up of one triangle and the irregular shape. I’ll refer to this triangle as triangle 1.
Take the area of that triangle.
.5*25*75=937.5
The base of the triangle you get by adding the base of the smaller triangle and the irregular shape. (51+24=75)

Inside the triangle you just took the area of (triangle 1) is another triangle (which I’ll refer to as triangle 2). Take the area of triangle 2.
.5*51*17=433.5

Subtract the area of triangle 1 by the area of triangle 2 and that’ll give you the area of the irregular shape.
937.5-433.5=504

So now you add the areas of the BIG triangle and the rectangle.
5760+2,400=8160
Make sure you subtract the irregular shape since it isn’t part of the lawn’s area.
8160-504=7656

So the lawn is 7656 square feet. Multiply it by .005. That equals 38.28. That’s how much fertilizer he needs to use.

Multiply 1.25 to 38.28 to get the amount of money he needs to spend.

47.85 dollars

I might’ve made a few mistakes but I hope my reasoning was at least understandable

Fiesta28 [93]3 years ago
5 0
When I look at this figure, I see two polygons.
1) A large trapezoid with sides 48 ft and 88 ft, and non-parallel sides 136 ft and the top side that includes the dashed part.
2) A small trapezoid with parallel sides 17 ft and 25 ft, and non-parallel sides 24 ft and the dashed segment on top.

The area of the lawn is the area of the large trapezoid minus the area of the small trapezoid.

Area of trapezoid = (B + b)h/2
where B = large base, b = small base, and h = height.
(The height is perpendicular to both bases.)

Large trapezoid:
A = (88 ft + 48 ft)(120 ft)/2 = 8160 ft^2

Small trapezoid:
A = (25 ft + 17 ft)(24 ft)/2 = 504 ft^2

Area of lawn = area of large trapezoid - area of small  trapezoid

Area of lawn = 8160 ft^2 - 504 ft^2

Area of lawn = 7656 ft^2

Weight of fertilizer:
0.005 * 7656 = 38.28 lb

Cost of fertilizer:
1.25 * 38.28 = $47.85
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Answer:

f(x) = -19/9(x + 3)² + 5

Step-by-step explanation:

Given the vertex, (-3, 5) and the point, (0, 14):

Use the following quadratic equation formula in vertex form:

f(x) = a(x - h)² + k

where:

(h, k) = vertex

a = determines whether the graph opens up or down, and makes the graph wide or narrow.

<em>h</em><em> </em>= determines how far left or right the parent function is translated.

<em>k</em> =  determines how far up or down the parent function is translated.

Plug in the values of the vertex, (-3, 5) and the given point, (0, 14) to solve for <em>a</em>:

f(x) = a(x - h)² + k

14 = a(0 + 3)² + 5

14 = a(3)² + 5

14 = a(9) + 5

Subtract 5 from both sides:

-14 - 5 = 9a

-19 = 9a

Divide both sides by 9 to solve for a:

-19/9 = 9a/9

-19/9 = a

Therefore, the quadratic function in vertex form is:

f(x) = -19/9(x + 3)² + 5

Please mark my answers as the Brainliest, if you find this helpful :)

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