Answer:
f(4) =11
Step-by-step explanation:
f(x)=3x-1
Let x = 4
f(4)=3*4-1
= 12-1
= 11
The range of the <em>quadratic</em> function y = (2 / 3) · x² - 6 is {- 6, 0, 18, 48}.
<h3>What is the range of a quadratic equation?</h3>
In this case we have a <em>quadratic</em> equation whose domain is stated. The domain of a function is the set of x-values associated to only an element of the range of the function, that is, the set of y-values of the function. We proceed to evaluate the function at each element of the domain and check if the results are in the choices available.
x = - 9
y = (2 / 3) · (- 9)² - 6
y = 48
x = - 6
y = (2 / 3) · (- 6)² - 6
y = 18
x = - 3
y = (2 / 3) · (- 3)² - 6
y = 0
x = 0
y = (2 / 3) · 0² - 6
y = - 6
x = 3
y = (2 / 3) · 3² - 6
y = 0
x = 6
y = (2 / 3) · 6² - 6
y = 18
x = 9
y = (2 / 3) · 9² - 6
y = 48
The range of the <em>quadratic</em> function y = (2 / 3) · x² - 6 is {- 6, 0, 18, 48}.
To learn more on functions: brainly.com/question/12431044
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Answer:
1/6y+1/6(y+12)-2... so the third one
Step-by-step explanation:
1/6y+1/6(y+12)-2
1/6y+1/6y+2-2
2/6y
Reduces to 1/3y
Answer:
500
Step-by-step explanation:
brainliest pls
These problems are based on the Pythagorean Theorem. The Pythagorean Theorem is a^2 + b^2 = c^2. If the two sides are equal, the triangle is a right triangle. If c^2 is less, the triangle is acute. If c^2 is more, the triangle is obtuse.
Obtuse: c^2 > a^2 + b^2
Acute: c^2 < a^2 + b^2
Right: c^2 = a^2 + b^2
#7 --- Obtuse
21^2 ___ 8^2 + 15^2
441 ___ 64 + 225
441 > 289
#8 --- Right
20^2 ___ 12^2 + 16^2
400 ___ 144 + 256
400 = 400
#9 --- Acute
6^2 ___ 4^2 + 5^2
36 ___ 16 + 25
36 < 41
Hope this helps!
