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kakasveta [241]
4 years ago
6

Hayden is a manager at a landscaping company. He has two workers to landscape an entire park, Cody and Kaitlyn. Cody can complet

e the project in 8 hours. Kaitlyn can complete the project in 6 hours. Hayden wants to know how long it will take them to complete the project together. Write an equation and solve for the time it takes Cody and Kaitlyn to complete the project together. Explain each step.
Mathematics
1 answer:
andrew11 [14]4 years ago
5 0

Cody ALONE = 8 hours 
Kaitlyn ALONE = 6 hours 
Let Joseph ALONE take j hours 
Cody ALONE in 1 HOUR = 1/8 of the work Kaitlyn ALONE in 1 hour = 1/6 of the work Joseph ALONE in 1 HOUR = 1/j of the work 
Since TOGETHER they take X hours, in 1 hour TOGETHER they complete 1 / X of the work 
1/8 + 1/6 + 1/j = 1/X 
1/j = 1/X - 1/8 - 1/6 = (24 - 3X - 4X ) /24X = (24 - 7X ) / 24X 
j = 24X / ( 24- 7X ) 
After completing the work value of X will be known , calculate j from the above formula ANSWER
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Pls help asap the best I can do is 50 points
lutik1710 [3]

Step-by-step explanation:

8.a.

a function is something that looks like

y = ax + b or similar.

it describes the way to calculate the result for whatever input value you can come up with.

so,

C = 12×d + 8

you could also say

C(d) = 12×d + 8

as, when you rent, you have to pay these $8 in any case, no matter how long you stay, and you need to pay $12 per day you stay.

funny thing is : you understood this perfectly well when doing b.

c.

the constant rate of change is always the factor of the input variable. here : 12

it is the ratio of (y change) / (x change)

or here (C change / d change).

it indicates that for any increase of d by 1 (staying one day longer) the charges C increase by 12.

9.a.

remember, what we just said about the rate of change ?

it is (result change) / (input change).

between 2010 and 2015

the input changed by +5 (from 2010 to 2015).

the result changed by +6.25 (from 37 to 43.25).

the rate of change is therefore

6.25/5 = 1.25 = 1 1/4 = 5/4

the function is therefore

population in millions = (years since 2010)×5/4 + 37

p = y×5/4 + 37

b.

now we want to find the number of years (y) so that the result of that equation is 50.

50 = y×5/4 + 37

13 = y×5/4

52 = 5y

y = 52/5 = 10.4

so, this will be during the 11th year after 2010 = 2021.

10.

be careful and concentrate.

you see that the sequence goes up 20, when n goes up 5 (and not just 1) ? there was your initial mistake.

a.

again, remember the change rate : it is result change / input change.

so, we have here 20/5 = 4.

so,

C(n) = 4×n + 50

b.

n = 12

C(12) = 4×12 + 50 = 98

c.

now we have C(n), and want to find for which n this is true.

C(n) = 78

78 = 4×n + 50

28 = 4×n

n = 7

after 7 visits the costs are 78.

there are the basic costs of 50 (for n = 0 or 0 visits) and then extra 4 for every visit.

d.

the x-axis is for the number of visits, the y-axis for the costs.

so, the line starts at the point (0, 50), and then passes through the points of the original table (5, 70), (10, 90), (15, 110). and if you want you can calculate the points for higher x (or number of visits).

4 0
3 years ago
Jim and Sean went to the diner and bought two egg scrambles. Jim also got a cup of coffee for a dollar. If their total bill was
Alex73 [517]

Answer:

If only Jim purchased a cup of coffee, we will subtract its cost from the total;

9.50 - 1.00 = 8.50

Assuming that the two purchased nothing else for breakfast, and that the cost of an egg scramble was the same for both, let's call the price of the egg scramble x.

Since they both bought eggs, then 2x = 8.50

x = $4.25, the price for each egg scramble

4 0
3 years ago
A specific automotive part that a service station stocks in its inventory has an 8% chance of being defective. Suppose many cars
mylen [45]

Answer:

6.23% probability that the fourth part retrieved from stock is the first defective

Step-by-step explanation:

For each part, we have that:

8% probability of being defective.

100-8 = 92% probability of not being defective.

The parts are independent of each other.

What is the probability that the fourth part retrieved from stock is the first defective?

The first three work correctly, each one with a 92% probability.

The fourth is defective, with an 8% probability.

P = 0.92*0.92*0.92*0.08 = 0.0623

6.23% probability that the fourth part retrieved from stock is the first defective

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4.2 is your answer.
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A ball with mass m kg is thrown upward with initial velocity 28 m/s from the roof of a building 17 m high. Neglect air resistanc
Nutka1998 [239]

a. At its maximum height, the ball has zero vertical velocity, so

-\left(28\dfrac{\rm m}{\rm s}\right)^2=2(-g)(y_{\rm max}-17\,\mathrm m)

\implies y_{\rm max}=57\,\mathrm m

b. The ball's height in the air y at time t is given according to

y=17\,\mathrm m+\left(28\dfrac{\rm m}{\rm s}\right)t-\dfrac g2t^2

Solve for t when y=0:

17+28t-4.9t^2=0\implies t\approx6.3\,\mathrm s

3 0
3 years ago
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