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1 year ago

A

Mathematics

1 answer:

kakasveta [241]1 year ago

5 0

Answer:

Your answer would be A.

Step-by-step explanation:

okay so, with a best fit line, it needs to match up with your points. unless your points go up evenly. its not going to connect to all your points.

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Find the equation of the line with a slope of 2/5 and containing the point (10,6).

Kipish [7]

Use the poin-slope form of the equation of a line:-

y - y1 = m(x - x1) (where m = slope and the point is (x1, y1))

Plugging in the given values:-

y - 6 = 2/5(x - 10)

multiplying through by 5:-

5y - 30 = 2(x - 10)

5y - 30 = 2x - 20

5y = 2x + 10

In standard form the equation is

2x - 5y = -10 (answer)

4 0

3 years ago

Someone pls help me!! thank you!!

romanna [79]

Final Answer is 4.5

= 4.5hours more time was used on games than on research.

6 0

3 years ago

First twelve mulitples of 4

Pachacha [2.7K]

Answer:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48

Step-by-step explanation:

4*1 = 4

4*2 = 8

4*3 = 12

and so on...

5 0

2 years ago

Read 2 more answers

in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference

allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

$\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}$

so that

$a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d$

$a_n=a_1+(n-1)d$

$33=8+(n-1)d$

$21=(n-1)d$

$n$ has to be an integer, which means there are 4 possible cases.

Case 1: $n-1=1$ and $d=21$ . But

$\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123$

Case 2: $n-1=21$ and $d=1$ . But

$\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123$

Case 3: $n-1=3$ and $d=7$ . But

$\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123$

Case 4: $n-1=7$ and $d=3$ . But

$\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123$

8 0

3 years ago

Erica babysits for 4 hours and is paid $33

Aleksandr-060686 [28]

Answer: a: 8.25 b: 49.5

Step-by-step explanation:

7 0

2 years ago