Answer:
Step-by-step explanation:
the answer cannot be 5. Why? Because the minimum will occur when 12 and 5 point in opposite directions like both are on the x axis pointing to 0 from the east and pointing to zero coming from the west.
12 - 5 = 7
You cannot get a result less than that.
Answer:
n= -9
Step-by-step explanation:
Simplifying
-2(n + 3) + -4 = 8
Reorder the terms:
-2(3 + n) + -4 = 8
(3 * -2 + n * -2) + -4 = 8
(-6 + -2n) + -4 = 8
Reorder the terms:
-6 + -4 + -2n = 8
Combine like terms: -6 + -4 = -10
-10 + -2n = 8
Solving
-10 + -2n = 8
Solving for variable 'n'.
Move all terms containing n to the left, all other terms to the right.
Add '10' to each side of the equation.
-10 + 10 + -2n = 8 + 10
Combine like terms: -10 + 10 = 0
0 + -2n = 8 + 10
-2n = 8 + 10
Combine like terms: 8 + 10 = 18
-2n = 18
Divide each side by '-2'.
n = -9
Simplifying
n = -9
Answer:
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Answer:
The system of inequalities is
y\geq 3x-2
y<-(1/5)x+2
Step-by-step explanation:
step 1
Find the equation of the solid blue line
Let
A(0,-2), B(1,1)
Find the slope of AB
m=(1+2)/(1-0)=3
The equation of the line into slope intercept form is equal to
y=mx+b
we have
m=3
b=-2 - ----> the point A is the y-intercept
substitute
y=3x-2 - -----> equation of the solid blue line
The solution of the inequality is the shaded area above the solid line
therefore
The first inequality is
y\geq 3x-2
C(0,2), D(5,1)
step 2
Find the equation of the dashed red line
Let
Find the slope of CD
m=(1-2)/(5-0)=-1/5
The equation of the line into slope intercept form is equal to
y=mx+b
we have
m=-1/5
b=2 ----> the point C is the y-intercept
substitute
y=-(1/5)x+2 -----> equation of the dashed red line
The solution of the inequality is the shaded area below the dashed line
therefore
The second inequality is
y<-(1/5)x+2
The system of inequalities is
y\geq 3x-2
y<-(1/5)x+2
