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Lelechka [254]
3 years ago
15

Solve (linear equation)

Mathematics
1 answer:
nydimaria [60]3 years ago
8 0
<span><span>−1/</span>2</span>‌x+<span><span>‌<span>1/3</span></span>‌</span>><span><span>‌<span>3/5</span></span>‌</span>Subtract 1/3 from both sides.<span><span><span><span><span>‌<span><span>−1/</span>2</span></span>‌x</span>+<span><span>‌<span>1/3</span></span>‌</span></span>−<span><span>‌<span>1/3</span></span>‌</span></span>><span><span><span>‌<span>3/5</span></span>‌</span>−<span><span>‌<span>1/3</span></span>‌</span></span></span><span><span><span>‌<span><span>−1/</span>2</span></span>‌x</span>><span><span>‌<span>4/15</span></span>‌</span></span>Multiply both sides by 2/(-1).<span><span><span>(<span><span>‌<span>2/<span>−1</span></span></span>‌</span>)</span>*<span>(<span><span>‌<span><span>−1/</span>2</span></span>‌x</span>)</span></span>><span><span>(<span><span>‌<span>2/<span>−1</span></span></span>‌</span>)</span>*<span>(<span><span>‌<span>4/15</span></span>‌</span>)</span></span></span><span>answer: x<<span>‌<span><span>−8/</span><span>15</span></span></span></span>
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u(x) = x5 – x4 + x2 and v(x) = –x2, which expression is equivalent to (StartFraction u Over v EndFraction) (x)?
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Answer:

Step-by-step explanation:

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\dfrac{u(x)}{v(x)}=\dfrac{x^5-x^4+x^2}{-x^2}=-x^3+x^2+1

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Nataly_w [17]

Which polynomial is equal to  (-3x^2 + 2x - 3) subtracted from  (x^3 - x^2 + 3x)?

<h3><u><em>Answer:</em></u></h3>

The polynomial equal to (-3x^2 + 2x - 3) subtracted from  (x^3 - x^2 + 3x) is x^3 + 2x^2 + x + 3

<h3><u><em>Solution:</em></u></h3>

Given that two polynomials are: (-3x^2 + 2x - 3) and (x^3 - x^2 + 3x)

We have to find the result when (-3x^2 + 2x - 3) is subtracted from  (x^3 - x^2 + 3x)

In basic arithmetic operations,

when "a" is subtracted from "b" , the result is b - a

Similarly,

When (-3x^2 + 2x - 3) is subtracted from  (x^3 - x^2 + 3x) , the result is:

\rightarrow (x^3 - x^2 + 3x) - (-3x^2 + 2x - 3)

Let us solve the above expression

<em><u>There are two simple rules to remember: </u></em>

  • When you multiply a negative number by a positive number then the product is always negative.
  • When you multiply two negative numbers or two positive numbers then the product is always positive.

So the above expression becomes:

\rightarrow (x^3 - x^2 + 3x) + 3x^2 -2x + 3

Removing the brackets we get,

\rightarrow x^3 - x^2 + 3x + 3x^2 -2x + 3

Combining the like terms,

\rightarrow x^3 -x^2 + 3x^2 + 3x - 2x + 3

\rightarrow x^3 + 2x^2 + x + 3

Thus the resulting polynomial is found

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