Answer:
Orion's belt width is 184 light years
Step-by-step explanation:
So we want to find the distance between Alnitak and Mintaka, which is the Orions belts
Let the distance between the Alnitak and Mintaka be x,
Then applying cosine
c²=a²+b²—2•a•b•Cosθ
The triangle is formed by the 736 light-years and 915 light years
Artemis from Alnitak is
a = 736lightyear
Artemis from Mintaka is
b = 915 light year
The angle between Alnitak and Mintaka is θ=3°
Then,
Applying the cosine rule
c²=a²+b²—2•a•b•Cosθ
c² =736² + 915² - 2×, 736×915×Cos3
c² = 541,696 + 837,225 - 1,345,034.1477702404
c² = 33,886.85222975954
c = √33,886.85222975954
c = 184.0838184897 light years
c = 184.08 light years
So, to the nearest light year, Orion's belt width is 184 light years
Answer:
B and C both equal 0.060 after evaluation.
Answer:Assuming all three, we shall find that each of the relations in 3:14 leads to a ... Then by 3:15 the relations AD//BC and AB||DE imply AD//CE, which excludes ... From 2:72, 3:11, 3:14, and 3:16 we deduce 3:19 If A, B, C are three distinct ... a point D lies between X and Y in AB/C if it belongs to XY/C, that is, if XY||CD
Step-by-step explanation:
X² <span>− 3x − 70=0
</span>x² + 7x - 10x − 70=0
x(x+7) - 10(x+7) = 0
(x+7)(x-10) = 0
x + 7 = 0 or x - 10 = 0
x = -7 x = 10
Answer: x=-7, x=10
The graph is Parabola or Graph of Quadratic Function.
The graph has minimum value, not maximum. So ( A ) is not correct for maximum part.
B is not correct for exponential part.
also C is not correct for discrete part as Quadratic graph is continuous.
So the answer is D.
