Answer:
The answer is B.
Step-by-step explanation:
If this is wrong im very very sorry!
A brainlist would be appreciated! I'm almost an expert!
In order for the ball to be used in the game, it must be able to meet the minimum and maximum weight requirements. These are the limits of the weight of the ball. If it exceeds the maximum limit of 16 ounces or below the minimum limit of 14 ounces, the ball will not be approved.
So, by adding 1.5 ounces, that would mean that the initial weight of the ball did not reach the minimum limit. The initial weight of the ball, denoted as x, have two possible values. The first value is the initial weight plus added with 1.5 ounces would reach 14 ounces.
x + 1.5 = 14
x = 12.5 ounces
The other scenario is when the initial weight is added to reach the maximum requirement of 16 ounces
x + 1.5 = 16
x = 14.5 ounces
From both answer, we could conclude that the initial weight has to be 12.5 ounces. If the initial weight were 14.5 ounces to begin with, there should be no need for air. It cans till be approved to be used.
For this question , you just need to divide 1 7/8 with 1/12
1 7/8 : 1/12
= 15/8 : 1/12
= 15/8 x 12/1
= 22.5 bags.
So i guess she can make around 22 full bags
hope this helps
Its a.
Lol taking forever to do stuff is fun.
Total no. of students - 140 students
Total no. of students from all schools= 140+70+35+105=350
school A= 140÷350×100=40./. (multiplying by 100 because it's the total percentage )
School B = 70÷350×100=20./.
School C = 105÷350×100=30./.
School D = 105÷350×100= 10./.
Consisting all the schools percentage it gives 100./.
Hope this helps
