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scZoUnD [109]
3 years ago
15

PLease Help!

Mathematics
2 answers:
Sergeu [11.5K]3 years ago
7 0
6x^8y^5....the degree can be found by adding the exponents....so the degree of this monomial is 13
Sphinxa [80]3 years ago
7 0
A degree of a monomial is the sum of the exponents of all its variables. So 8+5 would give u 13.
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lisa is painting a fence that is 26 feet long and 7 feet tall. A gallon of paint will cover 350 square feet. Write and slove a p
swat32
2<span>6 x 7 = 182 now divide that by 16 and your answer is 11.375 round that up to 12.</span>
5 0
4 years ago
1+4=52+5=123+6=218+11=?
Nikolay [14]
1+4=5
2+5=7
3+6=9
8+11=19
hope this helped:)

4 0
3 years ago
Read 2 more answers
Function A and Function B are linear functions. Compare the two functions and choose all that are correct.
Olegator [25]

Answer:

  2 .The slope of Function A is less than the slope of Function B

Step-by-step explanation:

A graph of Function A shows it has a y-intercept of 4, the same as that of Function B. (Statements 3 and 4 are not correct.)

The slope of Function A is 2, which is less than the slope of 3 that Function B has. (Statement 2 is correct; statement 1 is not.)

_____

<em>More detailed working</em>

The slope of Function A can be figured easily between the points with x-values that differ by 1:

  m = (y3 -y2)/(x3 -x2) = (24-22)/(10-9) = 2/1 = 2 . . . . . Fun A has slope of 2.

The slope of Function B is the coefficient of x in the equation: 3.

__

The y-intercept of Function A can be found starting with point-slope form:

  y -22 = 2(x -9)

  y = 2x -18 +22

  y = 2x +4 . . . . . . . slope-intercept form

The intercept of +4 is the same as that of Function B.

5 0
3 years ago
Read 2 more answers
Why is 1 + (−5) equal to −4?
ruslelena [56]

Answer:

because its 5 units to the left on a horizontal number line

8 0
4 years ago
Read 2 more answers
Find the equation of a circle with a center at (7,2) and a point on the circle at (2,5)?
monitta

Answer:

(x-7)^2+(y-2)^2=34

Step-by-step explanation:

We want to find the equation of a circle with a center at (7, 2) and a point on the circle at (2, 5).

First, recall that the equation of a circle is given by:

(x-h)^2+(y-k)^2=r^2

Where (<em>h, k</em>) is the center and <em>r</em> is the radius.

Since our center is at (7, 2), <em>h</em> = 7 and <em>k</em> = 2. Substitute:

(x-7)^2+(y-2)^2=r^2

Next, the since a point on the circle is (2, 5), <em>y</em> = 5 when <em>x</em> = 2. Substitute:

(2-7)^2+(5-2)^2=r^2

Solve for <em>r: </em>

<em />(-5)^2+(3)^2=r^2<em />

Simplify. Thus:

25+9=r^2

Finally, add:

r^2=34

We don't need to take the square root of both sides, as we will have the square it again anyways.

Therefore, our equation is:

(x-7)^2+(y-2)^2=34

4 0
3 years ago
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