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sergiy2304 [10]
4 years ago
10

The area of the trapezuim ?!

Mathematics
1 answer:
DedPeter [7]4 years ago
6 0
We Know, Area of Trapezium = (a+b)/2 * h
Where, a & b are parallel bases & h is height.

Here, we have a = 8, b = 18, h = 5
substitute them into the expression, as follows:
Area = (8+18)/2 * 5
A = 26/2 * 5
A = 13 * 5
A = 65

So, area would be 65 cm²

Hope this helps!
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HELLPPP PLEASE WILL GIVE BRAINLIEST ​
avanturin [10]

Answer:

25

Step-by-step explanation:

90-65=25

4 0
3 years ago
The length of a diagonal of a square is 7.5 mm. Find the area of the square.
dexar [7]
By Pythagoreans' theorem,

7.5² = l² × b²
56.25 = l² × b²

Since l = b
56.25 ÷ 2
= l²/b²
= 28.125 mm

∴ l = √28.125
= 5.3033 mm

Area of square
= √28.125 × √28.125
= 28.125 mm²
≈ 28.1 mm² (3s.f.)
7 0
3 years ago
What is 9 7/8 written as a decimaal?i will give brainliest,points,and friend requests.
I am Lyosha [343]

9 7/8 written as a decimal is 9.88

Work: So, The first thing I did was 9 (Whole Number) times the Denominator. After the Multiplication, I had gotten 72. I added 72 by the numerator which is 79. Then, I divided 79 by the denominator, and I had gotten 9.875, and I rounded it up to 9.88

I hope this helps, and you get this question correct. :)

8 0
3 years ago
A tunnel is built in form of a parabola. The width at the base of tunnel is 7 m. On
uysha [10]

Given:

The width at the base of parabolic tunnel is 7 m.

The ceiling 3 m from each end of the base there are light fixtures.

The height to light fixtures is 4 m.

To find:

Whether it is possible a trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel.

Solution:

The width at the base of tunnel is 7 m.

Let the graph of the parabola intersect the x-axis at x=0 and x=7. It means x and (x-7) are the factors of the height function.

The function of height is:

h(x)=ax(x-7)             ...(i)

Where, a is a constant.

The ceiling 3 m from each end of the base there are light fixtures and the height to light fixtures is 4 m. It means the graph of height function passes through the point (3,4).

Putting x=3 and h(x)=4 in (i), we get

4=a(3)((3)-7)

4=a(3)(-4)

\dfrac{4}{(3)(-4)}=a

-\dfrac{1}{3}=a

Putting a=-\dfrac{1}{3}, we get

h(x)=-\dfrac{1}{3}x(x-7)              ...(ii)

The center of the parabola is the midpoint of 0 and 7, i.e., 3.

The width of the truck is 4 m. If is passes through the center then the truck must m 2 m on the left side of the center and 2 m on the right side of the center.

2 m on the left side of the center is x=1.5.

A trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is possible if h(1.5) is greater than 2.8.

Putting x=1.5 in (ii), we get

h(1.5)=-\dfrac{1}{3}(1.5)(1.5-7)

h(1.5)=-(0.5)(-5.5)

h(1.5)=2.75

Since h(1.5)<2.8, therefore the trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is not possible.

6 0
3 years ago
celina measured the height of a window frame as 5.55 feet, but the actual height was 6 feet. What is the percentage of error in
skad [1K]
(6/5.55) * 100 = 108.11 %

The percent error is 108.11 %
6 0
3 years ago
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